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3 years ago

Find the sum of - 100.55 and 69.95.

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

8 0

Answer:

-30.6

Step-by-step explanation:

a negative and a positive number always gives us another negative number

Tanya [424]3 years ago

5 0

Answer:

-30.6

Step-by-step explanation:

You can use a calculator or you can think and be well if theres a number line theres a right part so -100.55 so then yo move 69.95 spaces

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A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi

viktelen [127]

Answer:

Side length = $\sqrt{\frac{A}{3} }$ cm , Height = $\frac{1}{2} \sqrt{\frac{A}{3} }$ cm , Volume = $\frac{A\sqrt{A}}{6\sqrt{3} }$ cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

$y = \frac{A - x^{2} }{4x}$

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( $\frac{A - x^{2} }{4x}$ )

V = $\frac{Ax - x^{3} }{4}$

To find max volume put V' = 0

So taking derivative equation becomes

$\frac{A - 3 x^{2} }{4} = 0$

A = 3 $x^{2}$

$x^{2}$ = $\frac{A}{3}$

x = $\sqrt{\frac{A}{3\\} }$

put value of x in equation 1

y = $\frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }$

y = $\frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }$

y = $\frac{1}{2} \sqrt{\frac{A}{3} }$

So the volume will be

V = $x^{2}$ × y

Put values of x and y from equation 2 & 3

V = $\frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )$

V = $\frac{A\sqrt{A}}{6\sqrt{3} }$

8 0

2 years ago

Margo added three multi-digit decimal numbers. The first number was 5.19. The second number was 10 times the first number. The t

Anika [276]

Answer: 576.09

Step-by-step explanation:

First number = 5.19.

The second number was 10 times the first number which will be:

= 5.19 × 10

= 51.9

The third number was 10 times the second number. Thus will be:

= 51.9 × 10

= 519

The sum of the numbers will be:

= 1st number + 2nd number + 3rd number

= 5.19 + 51.9 + 519

= 576.09

7 0

2 years ago

solve -9p - 5m = 60 how do you solve this step by step please. not just the answer I need to learn how you do this problem. solv

Scrat [10]

-9p - 5m = 60
-9p - 5m + 5m = 5m + 60
-9p = 5m + 60
-9 -9
p = ⁻⁵/₉m - 6²/₃

You have to add 5m on each side in order to find the value of p. then, you have to divide it by -9 in order to find the value of p.

5 0

2 years ago

You move left 1 unit and down 9 units. You end at (-4, -4). Where did you start?

hodyreva [135]

Answer:

(5,13) I think, I wasn't very good at this sorta thing lol

4 0

2 years ago

Read 2 more answers

Over a nine-month period, OutdoorGearLab tested hardshell jackets designed for ice climbing, mountaineering, and backpacking. Ba

Yuri [45]

Answer:

(a) The mean is 65.9, the median is, 66.5 and the mode is. 61.

(b) The first and third quartiles are 61 and 71 respectively.

Step-by-step explanation:

The ratings of 20 top-of-the line jackets, arranged in ascending order are as follows:

S = {42 , 53 , 54 , 61 , 61 , 61 , 62 , 63 , 64 , 66 , 67 , 67 , 68 , 69 , 71 , 71 , 76 , 78 , 81 , 83}

(a)

Compute the mean as follows:

$\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}=\frac{1}{20}\times 1318=65.9$

Compute the median as follows:

For an even number of values the median is the average of the middle two values.

$M=\frac{10^{th}obs.+11^{th}obs.}{2}=\frac{66+67}{2}=66.5$

Compute the mode as follows:

The mode of a dataset is the term that occurs most of the time.

$m=61$

Thus, the mean is 65.9, the median is, 66.5 and the mode is. 61.

(b)

The first quartile is the median of the first half of the data set.

S₁ = {42 , 53 , 54 , 61 , 61 , 61 , 62 , 63 , 64 , 66}

$Q_{1}=\text{Median of }S_{1}=\frac{5^{th}obs.+6^{th}obs.}{2}=\frac{61+61}{2}=61$

The third quartile is the median of the second half of the data set.

S₂ = {67 , 67 , 68 , 69 , 71 , 71 , 76 , 78 , 81 , 83}

$Q_{3}=\text{Median of }S_{2}=\frac{15^{th}obs.+16^{th}obs.}{2}=\frac{71+71}{2}=71$

Thus, the first and third quartiles are 61 and 71 respectively.

(c)

The <em>p</em>th percentile is a data value such that at least p% of the data set is less-than or equal to this data value and at least (100 - p)% of the data-set are more-than or equal to this data value.

Use the Excel formula "=PERCENTILE.INC(array,0.9)" to compute the 90th percentile.

The value of the 90th percentile is, 78.3.

This value implies that 90% of the ratings are less than 78.3.

7 0

2 years ago