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3 years ago

Does this set of ordered pairs represent a function? Why or why not? {(–5, –5), (–1, –2), (0, –2), (3, 7), (8, 9)}

Mathematics

2 answers:

baherus [9]3 years ago

8 0

Answer:

The correct is D: Yes because every x-value corresponds to exactly one y-value: Apex

Step-by-step explanation:

kkurt [141]3 years ago

7 0

C is the choice for your answer

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What's the equation for y?

-Dominant- [34]

The aswer is easy it is d

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3 years ago

Rahul has 5 BLUE BLOCKS, 3 PINK BLOCKS AND 4 GREEN BLOCKS. He wants to count the total number of blocks he is having. In how man

arsen [322]

Answer:

a) He can find the answer in one way

b) We make use of Addition property of mathematics

c) Total number of blocks = 12 blocks

Step-by-step explanation:

a) He can find the answer in one way

b) We make used of addition property of mathematics

c) The total number of blocks he is having is calculated as:

Blue blocks + Pink blocks + Green blocks

Where

Blue blocks = 5

Pink blocks = 3

Green blocks = 4

Hence:

Total number of blocks = 5 + 3 + 4 = 12 block

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3 years ago

Name the transformation in the picture.

olchik [2.2K]

The answer is translation

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3 years ago

A large box shaped arena has a rectangular floor that measures 200 feet by 150 feet and a flat ceiling that is 35 feet above the

Andrew [12]

200 I’m pretty sure Yea your gonna have to trust your gut with this one

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3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \

Kisachek [45]

Answer:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2$

Step-by-step explanation:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?$

We can use Part I of the Fundamental Theorem of Calculus:

$\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}$

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

$\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}$

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

$\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

$\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}$

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

$\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

$\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]$
where u represents any function other than a variable

For the first term, replace $\text{t}$ with $2x$ , and apply the chain rule to the function. Do the same for the second term; replace

$\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)$

Simplify the expression by distributing $2$ and $2x$ inside their respective parentheses.

$[-(8x^2 +2)] + (2x^5 + 2x)$
$-8x^2 -2 + 2x^5 + 2x$

Rearrange the terms to be in order from the highest degree to the lowest degree.

$\displaystyle2x^5-8x^2+2x-2$

This is the derivative of the given integral, and thus the solution to the problem.

6 0

3 years ago