All categories

3 years ago

Round 3,942,588 to the nearest thousand.

Mathematics

2 answers:

DerKrebs [107]3 years ago

8 0

3,943,000...........................

olchik [2.2K]3 years ago

5 0

Hey there! :D

3,942,588

The thousandths is where the 2 is.

If the number behind the 2 is 5 or greater, we round up to 3.

It is, so round up:

3,943,000 <== rounded number

I hope this helps!
~kaikers

You might be interested in

What is the area of this trapezoid? 10cm 5cm 12cm 1.5cm

lutik1710 [3]

Area of a trapezoid = a+b+c x h

10 + 5 +12 = 27 x h

27h = 27 x 1.5 = 40.5

8 0

3 years ago

A plane traveled 1463 miles to Moscow and back. The trip there was with the wind. It took 11 hours. The trip back was into the w

Studentka2010 [4]

The speed of plane is 105 miles per hour and speed of wind is 28 miles per hour.

Step-by-step explanation:

Given,

The distance traveled by plane = 1463 miles

The trip with the wind took 11 hours.

The trip took 19 hours against the wind.

Let,

s be the speed of plane and w be the speed of wind.

Therefore;

Speed with the wind = s+w

Speed into the wind = s-w

We know that;

Distance = Speed * Time

Therefore;

Equation for trip taken with wind.

1463 = 11(s+w)

Dividing both sides by 11

$\frac{1463}{11}=\frac{11(s+w)}{11}\\133=s+w\\s+w=133\ \ \ Eqn\ 1$

Equation for trip taken into the wind

1463 = 19(s-w)

Dividing both sides by 19

$\frac{1463}{19}=\frac{19(s-w)}{19}\\77=s-w\\s-w=77 \ \ \ Eqn\ 2$

Adding Eqn 1 and 2

$(s+w)+(s-w)=133+77\\s+w+s-w=210\\2s=210$

Dividing both sides by 2

$\frac{2s}{2}=\frac{210}{2}\\s=105$

Putting s=105 in Eqn 1

$105+w=133\\w=133-105\\w=28$

The speed of plane is 105 miles per hour and speed of wind is 28 miles per hour.

3 0

3 years ago

6785∆4 is a 6-digit number with one of its digit represented by ∆. What can be the value of ∆ if 6785∆4 is divisible by 9

Aliun [14]

Answer:

Step-by-step explanation:

If the sum of the digits of a number is divisible by 9, then the number is divisible by 9.

So 6+7+8+5+Δ+4 = Δ + 30 has to be divisable by 9, and of course 0≤Δ≤9

36 is divisable by 9, so Δ has to be 6.

6 0

3 years ago

What is an example of a non-random sample?(math)

Sauron [17]

Is the question multiple choice or do you have to write your own down

5 0

3 years ago

A ball is thrown into the air. The path it takes is modeled by the equation: -3t+24t = h, where t is the time in seconds and h i

astra-53 [7]

Given:

The given equation is:

$-3t^2+24t=h$

Where, t is the time in seconds and h is the height of the ball above the ground, measured in feet.

To find:

The inequality to model when the height of the ball is at least 36 feet above the ground. Then find time taken by ball to reach at or above 36 feet.

Solution:

We have,

$-3t^2+24t=h$

The height of the ball is at least 36 feet above the ground. It means $h\geq 36$ .

$-3t^2+24t\geq 36$

$-3t^2+24t-36\geq 0$

$-3(t^2-8t+12)\geq 0$

Splitting the middle term, we get

$-3(t^2-6t-2t+12)\geq 0$

$-3(t(t-6)-2(t-6))\geq 0$

$-3(t-2)(t-6)\geq 0$

The critical points are:

$-3(t-2)(t-6)=0$

$t=2,6$

These two points divide the number line in 3 intervals $(-\infty,2),(2,6),(6,\infty)$ .

Intervals Check point $-3(t-2)(t-6)\geq 0$ Result

$(-\infty,2)$ 0 $(-)(-)(-)=(-)$ False

$(2,6)$ 4 $(-)(+)(-)=+>0$ True

$(6,\infty)$ 8 $(-)(+)(+)=(-)$ False

The inequality is true for (2,6) and the sign of inequality is $\geq$ . So, the ball is above 36 feet between 2 to 6 seconds.

$6-2=4$

Therefore, the required inequality is $-3t^2+24t\geq 36$ and the ball is 36 feet above for 4 seconds.

3 0

3 years ago