Answer:
C. 3.4 feet
Step-by-step explanation:
Let, the amount of increase be 'x' feet.
As, the length and width of the garden are 20 ft and 12 ft respectively.
It is given that the area of the new garden is 360 ft²
Since, the length and width are increased by 'x'.
The new length and width are (x+20) ft and (x+12) ft respectively.
So, we get,
New area, 
= length × breadth = (x+20) × (x+12)
i.e. 360 = 
i.e. 
i.e. (x+35.4)(x-3.4)=0
i.e. x = -35.4 and x= 3.4
Since, the value of x cannot be negative.
Thus, x = 3.4 feet.
It Is Going To Be 5 Because 15÷3=5 And 15÷5=3 And 5×3=15 3×5=15
9514 1404 393
Answer:
(3, 2)
Step-by-step explanation:
Reflection across y=x swaps the coordinates:
(x, y) ⇒ (y, x)
Dilation by a factor of 1/2 multiplies each coordinate by 1/2.
(x, y) ⇒ (x/2, y/2)
The combination of these transformations gives you ...
(x, y) ⇒ (y/2, x/2)
(4, 6) ⇒ (3, 2)
Answer:
3x−1
Step-by-step explanation:
1 Split the second term in 6{x}^{2}+x-16x
2
+x−1 into two terms.
\frac{6{x}^{2}+3x-2x-1}{4{x}^{2}-1}
4x
2
−1
6x
2
+3x−2x−1
2 Factor out common terms in the first two terms, then in the last two terms.
\frac{3x(2x+1)-(2x+1)}{4{x}^{2}-1}
4x
2
−1
3x(2x+1)−(2x+1)
3 Factor out the common term 2x+12x+1.
\frac{(2x+1)(3x-1)}{4{x}^{2}-1}
4x
2
−1
(2x+1)(3x−1)
4 Rewrite 4{x}^{2}-14x
2
−1 in the form {a}^{2}-{b}^{2}a
2
−b
2
, where a=2xa=2x and b=1b=1.
\frac{(2x+1)(3x-1)}{{(2x)}^{2}-{1}^{2}}
(2x)
2
−1
2
(2x+1)(3x−1)
5 Use Difference of Squares: {a}^{2}-{b}^{2}=(a+b)(a-b)a
2
−b
2
=(a+b)(a−b).
\frac{(2x+1)(3x-1)}{(2x+1)(2x-1)}
(2x+1)(2x−1)
(2x+1)(3x−1)
6 Cancel 2x+12x+1.
\frac{3x-1}{2x-1}
2x−1
3x−1
