For the first one. The complement is you subtract 90-51 = 39
The second one the supplement is 180-61= 119
Answer: 10/36
When a pair of fair dice are rolled , the total possible cases are (6 × 6) = 36. Out of these 36 cases the following 10 cases are favors(giving the sum > 8) for the happening of the event . These 10 cases are (3, 6), (4, 5), (4, 6),(5, 4), (5, 5), (5, 6) , (6, 3), (6, 4), (6, 5), & (6, 6)
I am not going to give you the answer, but I am going to tell you how to do it. You first put 18 over 1, and multiply that by one half. (You multiply across.)
Can you please show a picture of the graph? Otherwise, no one can help you. Or at least tell me what is the graph.