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tankabanditka [31]
3 years ago
10

Find the value of the variable and BC, if B is between A and C. AB = 5x, BC = 3x-1, AC = 47

Mathematics
1 answer:
schepotkina [342]3 years ago
4 0

Answer:

17

Step-by-step explanation:

AC = AB + BC

Since we know what each variable equals, we can write out the equation as shown:

47 = 5x + 3x - 1

Combining like terms:

47 = 8x - 1

Add 1 on both sides:

48 = 8x

Divide 8 on both sides:

X = 6

Now that we know what X equals, we can solve BC.

BC = 3(6) - 1

BC = 18 - 1

BC = 17

Therefore BC = 17.

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den301095 [7]

Answer:

52.3m^2

Step-by-step explanation:

Use these formulas

A=\pi rl+\pi r^2\\l=\sqrt{r^2+h^2}

Now solve

A=\pi r(r+\sqrt{h^2+r^2} )\\=\pi *2*(2\sqrt{6^2+2^2} )\\=52.3m^2

4 0
3 years ago
Which picture shows the correct graph of |x|=3?
suter [353]

Answer:

[see picture]

Step-by-step explanation:

There were no given choices, but I did graph the equation using Desmos.

Choose the answer that is closest to this:

8 0
3 years ago
A jewelry store offers its own brand of customizable charm bracelets. You are able to choose from 9
Elis [28]

Answer:

By the way that it is worded, I believe that you are only allowed to put 1 charm on the bracelet, so there are 9 ways to pick a charm.

Hope this helps(and also if you have a more refined wording please put it in the comments)!

4 0
3 years ago
What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as
Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

P(C | J) = 0.15 / (0.25)

P(C | J) = 0.6 = 0.60

5 0
2 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT
fredd [130]
Here you go!! It's always best to graph these questions, if you have graph paper near.
If not there are online graphing websites to use!! :))

ANSWER: Choice D (4th answer)

7 0
2 years ago
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