Since one equation has a negative y and the other has a positive y, I'm going to use those since they cancel each other out. Before that, the two y's need to be equal to each other.
x+2y=6
x-y=3
Multiply the bottom equation by two so then you have:
x+2y=6
2x-2y=6
The y's now cancel out:
x=6
2x=6
Add them together
3x=12
Divide
x=4.
To find y, plug x into either equation (*don't have to do both, but I will)
(4)+2y=6
(4)-y=3
Subtract four
2y=2
-y=-1
Divide each
2y/2 = 2/2
y=1
-y/-1 = -1/-1
y=1
The answer is:
x=4
y=1
I hope that helps!
according to the picture we have:
x.y=4.7
(7)x(7)y=49xy=(49)(4.7)=230.3
Answer:
-(x+2)/(x+8)
Step-by-step explanation:
( x^2 -x-6)
------------------
24 - 5x -x^2
Factor out a minus sign from the denominator
( x^2 -x-6)
------------------
-( x^2 +5x -24)
Factor the numerators and the denominators
( x-3) (x+2)
------------------
-( x+8)(x-3)
Cancel like terms
x+2
------------------
-(x+8)
Answer:
x=5
Step-by-step explanation:
That is your answer .
First you do 4x-3+3=2x+7+3
then,4x=2x+10,then
subtract 2x from both side
4x-2x=2x+10-2x
simplify
2x=10
divide both sides by 2 2x/2=10/2
simplfy and you get x=5
Hope this helps :)
Answer:
4th one
Step-by-step explanation:
must be ![\sqrt[6]{x^{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7Bx%5E%7B5%7D%20%7D)