If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is foun
1 answer:
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Answer:
A.
Step-by-step explanation:
Given:
Volume of the cylindrical container before dilation,
Scale factor of the dilation,
Therefore, the volume of the dilated cylinder is given as:
Plug in 1 gal for and
for SF. Solve for
. This gives,
Therefore, the volume of the dilated cylinder is gallons.
Answer:
Option A is correct
Step-by-step explanation:
The given equation is
h = -16t^2+6t+4
When the ball will hit the ground, height h = 0
Putting value of h = 0
0 = -16t^2+6t+4
Now solving to find the value of t
=> -16t^2+6t+4 = 0
Multiply with -1
16t^2-6t-4=0
Using quadratic formula to find value of t
a= 16, b= -6 and c= -4
Putting values,
Since time cannot be negative, so t = 0.721 or 0.72
So, Option A is correct