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3 years ago

11

Ok so for the past day I have been answering lots of questions and I have A LOT of points so I will be giving out points every d

ay. o and solve this so I won't be reported
10+20= ?

2 answers:

AnnyKZ [126]3 years ago

4 0

The answer is definitely 30 :) thanks for the points!

Anna11 [10]3 years ago

3 0

Answer:

30

Step by Step:

( 69,420 = 69,000 + 420 ) = 30

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Shikha deposited Rs 2000 in a bank which pays 6% simple interest. She withdrew Rs 700 at the end of the first year. What will be

grandymaker [24]

Rate of interest is given as 6% and Principle amount as Rs2000
Interest after 1 year= P*R*T/100 = 2000*6*1/100 = Rs 120
Net amount at the end of first year= Principle+ interest-Amount withdrawn=2000+120-700= Rs 1420
For the next 2 years, simple interest will be paid at the rate of 6% on the amount of Rs 1420 which is = 1420*6*2/100 =Rs 170.40
Balance after 3 years= 1420+170.40=Rs 1590.40

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3 years ago

Which expression shows how 8⋅54 can be rewritten using the distributive property?

Dmitrij [34]

Answer:

8 • 54=8 • 50 + 8 • 4

Option C is the right answer

Step-by-step explanation:

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2 years ago

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Can you tell me what 4% of ? is 56 days

mars1129 [50]

The answer is
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4 years ago

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myrzilka [38]

-2x + 16 = x + 28
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3 years ago

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A communications company has developed three new designs for a cell phone. To evaluate consumer response, a sample of n = 120 co

defon

Answer:

The answer is "Its results are not consistent with its three designs Yes. Its results show significant differences between both the three designs."

Step-by-step explanation:

Following are the distribution of preference:

$Design 1 =54 \\\\ Design 2=38 \\\\\ Design 3=28 \\\\$

$Design \ \ \ \ \ \ \ \ \ \ O_i \\ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 54 \\2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 38\\3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 28 \\Total \ \ \ \ \ \ \ \ \ \ 120$

An expected frequency( $E_i$ ) has 40 Null hypotheses to take n=120.to each design:

The effects of the three designs are standardized

Inaccurate.

Hypothesis Alternative:

The effects of the three prototypes are not uniform

Degrees Of freedom $=(n-1)=(3-1)=2$

$H_o, x^2 \ test\ statistic \ \sum_i {\frac{(O_i -E_i)^2}{E_i}} \\$

$= \frac{(54 -40)^2}{40}+\frac{(38-40)^2}{40} + \frac{(28-40)^2}{40}\\\\=49+0.1+3.6\\\\=8.6$

Chi-squared distribution critical value at $\alpha = 0.05 (x^2 _{0.052})=5.99$

Since $x^2, a$ value $> x^2 -$ table of $\alpha =0.05 =5.99$ is determined.

So $H_o$ is rejected.

4 0

3 years ago