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WARRIOR [948]
3 years ago
7

1/ Assume that the distribution of residuals is approximately normal with mean 0 cm and standard deviation 5.9cm. What percent o

f the residuals are greater than 8cm? Justify your answer.
2/ Base on your answer on part 1, would it be surprising to randomly select a high school senior from the high school with a foot length of 20cm and a height greater than 165cm? Justify your answer.
Mathematics
1 answer:
Xelga [282]3 years ago
6 0

Answer:

1. 8.576%

2. Yes

Step-by-step explanation:

1. Use the calculator

Enter: normalcdf(8, E99, 0, 5.9)

This is equal to .08756.

Convert this number into a percent = 8.756%

2.

First, calculate the residual

Residual = Observed - Predicted = 165 - 2.599(20) + 105.08 = 7.94

Use the calculator

Enter: normalcdf(7.94, E99, 0, 5.9)

This is equal to .0892.

Convert this number into a percent = 8.92%

This would be surprising, because the chance of this happening is very low.

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3x^2+7x+3<br> + 5x^2+12x
Dvinal [7]

Answer:

8x^2+19x

Step-by-step explanation:

Simplify the expression by combining like terms. Terms which look a like and sound a like should be added together.

3x^2+7x+3+5x^2+12x

x^2 terms: 3x^2+5x^2=8x^2

x terms: 7x+12x=19x

constants: 3

Together is is 8x^2+19x+3.

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The cost of renting a chain saw is $3.90 per hour plus $6.50 for a cán
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prisoha [69]
192 gymnastics members
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2-4/6-2=
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3 years ago
Need help with a simple problem 2^x=3^x+1
KiRa [710]
For x\ \textgreater \ 0, 2^x\ \textless \ 3^x, all the more 2^x\ \textless \ 3^x+1, therefore no solution.

For x=0, we have 2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2. Obviously that' false.

For x\ \textless \ 0 both 2^x and 3^x, where 2^x\ \textgreater \ 3^x, belong to the range (0,1), then 3^x+1 belong to the range (1,2).
Those ranges don't have a common part, therefore, again, no solution.

So, the equation 2^x=3^x+1 doesn't have a solution.

4 0
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