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2 years ago

9

Help asap! Please! Much appreciated!

1 answer:

stiv31 [10]2 years ago

5 0

Area of the parallelogram = 20 x 16 = 320
Area of the triangle on top = 1/2 x 20 x 8 = 80
Total = 320 + 80 = 400 square inches

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Maximilian had 4/5 bag of trail mix. He divided the trail mix equally among 5 friends. What fraction of the full bag of trail mi

Basile [38]

. Given situation: => Maximilian had 4/5 of bag of trail mix. He divided this trail mix to his 5 friends. Find the fraction that each of his friend will have if he equally divided this to them. => Convert to decimal first 4/5 = 0.8 the dividen 5 = the divisor Let’s start dividing: => 0.8 / 5 => 0.16, now we have the decimal value, let’s convert this to fraction. => 0.16 = 16/100 let’s simplify => 4/25

7 0

2 years ago

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Do number 4 please DONT get it wrong or i block report, i really need help please :)

andriy [413]

Area of the figure = 30.28 m²

Solution:

The given image is splitted into two shapes.

One is rectangle and the other is semi-circle.

Length of the rectangle = 6 m

Width of the rectangle = 4 m

Area of the rectangle = length × width

= 6 m × 4 m

= 24 m²

Area of the rectangle = 24 m²

Diameter of the semi-circle = 4 m

Radius of the semi-circle = 4 m ÷ 2 = 2 m

Area of the semi-circle = $\frac{1}{2} \ \pi r^2$

$$=\frac{1}{2} \times 3 .14 \times 2^2$

$=6.28$

Area of the semi-circle = 6.28 m²

Area of the figure = Area of the rectangle + Area of the semi-circle

= 24 m² + 6.28 m²

= 30.28 m²

Area of the figure = 30.28 m²

3 0

3 years ago

What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0

Free_Kalibri [48]

Answer:

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}$

Hence, ption B is true.

Step-by-step explanation:

Given the expression

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

solving the expression

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

as

$\sqrt{x^2y^3}=xy\sqrt{y}$

$2\sqrt{x^3y^4}=2xy^2\sqrt{x}$

so the expression becomes

$\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}$

Group like terms

$=2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}$

Add similar elements

$=2xy^2\sqrt{x}+2xy\sqrt{y}$

Therefore, we conclude that:

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}$

Hence, option B is true.

6 0

2 years ago

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Solve the equation 5=1/2 v-3 <br><br> v=?

olya-2409 [2.1K]

5=1/2v-3
5=1/2v
+3 +3
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3 years ago

The sum of three consecutive even numbers 86. Select all the equations below that represent this situation.

Elena-2011 [213]

Answer:
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B = 3X+6 =(X+1)+(X+2)+(X+3)
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D = not (3X+3)

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2 years ago