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Vlada [557]
3 years ago
6

Use quadratic equation to find the roots of the following equations

Mathematics
2 answers:
AleksAgata [21]3 years ago
8 0
3x - 1 = -2x^2
= 2x^2 + 3x -1
= -+ 3√3^2 - (4)(2)(-1)/ 2x2
-+3√9+8/ 4
-+3√ 17/4
-+3√ 4.5
-3√4.5. or +3√4.5
-3 + 2.121 or. +3+2.121
x = -0.869 or x= 5.121


hope it helps
sertanlavr [38]3 years ago
3 0
See the attachment below.

Hope it helps!

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One spinner has three equally sized sectors numbered 1, 2, and 3. A second spinner has two equally sized sectors labeled Top (T)
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I would say, well, if there are 3 sides that are equal on spinner 1. They are equal. But, we are focusing on spinner two that has two sides. If there is only 2 equal sides then, they would have to be straight across from each other. So that is 180. 360 is full circle. take away 180 to get answer. 
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I hope this helped. And sorry if it is not the correct answer. But that is how I would of answered it
4 0
3 years ago
Read 2 more answers
Consider a steel guitar string of initial length L=1.00 meter and cross-sectional area A=0.500 square millimeters. The Young's m
Goshia [24]

Answer:

15mm

Step-by-step explanation:

we are looking for extension

To get Extension you need the original length and the strain both of which you are given

initial length L = 1.00m

the area A = 0.5mm² = 0.5 mm² = 0.5 x 10⁻⁶ m² ( we are changing to metres squared)

E = 2.0 x 10¹¹ n/m², Young's modulus

P = 1500N, the applied tension

Now to Calculate the stress.

σ = P/A (force/area) = (1500 N)/(0.5 x 10⁻⁶ m²) = 3 x 10⁹ N/m²

Also, Let β =  the stretch of the string.

Then the strain is

ε = β/L (extension/ original length)

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Therefore β/(1 m) = 0.015β = 0.015 m = 15 mm

Answer:  15 mm

8 0
3 years ago
Six pyramids are shown inside of a cube. The height of the cube is h units. Six identical square pyramids can fill the same volu
MAXImum [283]

Answer:

(A)The height of each pyramid is One-half h units.

Step-by-step explanation:

Height of the Cube = h units

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Base of the square pyramid = h units

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\text{Volume of One Pyramid}=\dfrac{1}{3}*h^2*Height

\text{Volume of Six Pyramids}=6*\dfrac{1}{3}*h^2*Height\\=(2h^2*Height)\:cubic\:units

Since Volume of the Cube = Volume of Six Square Pyramids

Then:

2h^2*Height=h^3\\Height=\dfrac{h^3}{2h^2} \\$Height of each pyramid =\dfrac{1}{2}h \:Units

5 0
3 years ago
Read 2 more answers
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andreev551 [17]

Answer:

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Step-by-step explanation:oklook

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Answer:

Does this help in any way?

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