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Pani-rosa [81]
3 years ago
9

A circle has a radius of 2.6 centimeters.What is the circumference,in centimeters,of the circle?

Mathematics
2 answers:
leva [86]3 years ago
8 0
The circumference would come to 16.328cm2
Tju [1.3M]3 years ago
6 0
37.699cm

Hope this helped!
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Please help due soon!!!
butalik [34]

Hey there!


Question #1.
2^6 + (2^3)^3

= 64 + (8)^3

= 64 + 8^3

= 64 + 512

= 576


Therefore, the answer should be:

Option A. 576


Question #2.
11^-4 * 11^8

= 1/14,641 * 214,358,881

= 14,641

≈ 11^4

Therefore, the answer should be:

Option C. 11^4


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

3 0
2 years ago
Read 2 more answers
yuri has a rope 12 meters long. he cuts it into pieces that are each 2 meters long. what fraction of the rope is one piece
Lelu [443]
So the numerator of your fraction (the top number) is the amount that was cut. The denominator (the bottom number) is the total amount of rope. So, your fraction would be 2/12. You can still simplify that by dividing both the numerator and denominator by 2 and end up with 1/6. Does that make sense? If you need any more help, go ahead and message me :)
6 0
2 years ago
You own a lawn care business. in a typical week you drive 600 miles and use 40 gallons of gasoline. gasoline costs $1.25 per gal
iVinArrow [24]
42.50$ ?        21 times 1.25  plus 13 times 1.25 = 42.50?  
4 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
Help please i need to pass
stellarik [79]

Answer:

hi! i dont have the answer because i suck at school lol XD but, i actually have the same question! do you know the answer yet?:] sorry to bother you if you dont.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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