Yes so i do need to doing the times and multipics then get a fraction then u will get tot eh answer
Answer:
ma'am or sir... there is no picture attached... but whats the question?
Step-by-step explanation:
n=3; We need a third degree polynomials with the following given zero's: 2 and 5i are zeros; f(-1)=156.
Since these are solutions
x = 2 ; x = 5i. Since imaginaries travel in pairs, the other answer is x= -5i.
We have (x-2)(x-5i)(x+5i) = 0
Now,
f(-1) = (-1-2)(-1-5i)(-1+5i) = 156.
f(-1) = (-3)(26) = -78.
But -78 x -2 = 156, so our polynomial becomes
Y= -2x (<em>x</em> - 2 ) x (<em>x </em>to the power of 2 + 25) = 0
The greatest common factor is...
5a
I got this by...
10: 1,2,5,10
15: 1,3,5,15
25: 1,5,25
The GCF is 5 for the numbers.
For the a's, it's...
a: a
a^3: a×a×a
a^6: a×a×a×a×a×a
The GFC is a.
Then multiple 5 and a, and you get...
5a
The GFC is...
5a
Hope this helps!
