<span>Find the inverse of the given function.
f(x) = -1/2√x + 3, x ≥ -3
I will have to assume that you meant f(x) = -(1/2)sqrt(x) + 3. If you actually meant f(x) = -(1/2)sqrt(x+3), then obviously the correct result would be different.
1. Replace "f(x)" by "y:" y </span>= -(1/2)sqrt(x) + 3
2. Interchange x and y: x = -(1/2)sqrt(y) + 3
3. Solve for y: x-3=-(1/2)sqrt(y), so that 2(3-x)= sqrt(y) and y=+sqrt(2[3-x])
4. Replace "y" with
-1
f (x) = sqrt(2[3-x])
Here, there are restrictions on x, since the domain of the sqrt function does not include - numbers. The domain here is (-infinity,3]
Can you add on. What rational numbers are you referring to?
6x+7y=32 and 2x+5y=16
if you add the two equations you get the first answer and if you subtract the two equations you get the second answer
2 (6) - 3 (-3) , 12 - -9 , 12 + 9 , 21
