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Nataliya [291]
3 years ago
15

On December 31, 2020, Berclair Inc. had 200 million shares of common stock and 3 million shares of 9%, $100 par value cumulative

preferred stock issued and outstanding. On March 1, 2021, Berclair purchased 24 million shares of its common stock as treasury stock. Berclair issued a 5% common stock dividend on July 1, 2021. Four million treasury shares were sold on October 1. Net income for the year ended December 31, 2021, was $150 million. Also outstanding at December 31 were 30 million incentive stock options granted to key executives on September 13, 2016. The options were exercisable as of September 13, 2020, for 30 million common shares at an exercise price of $56 per share. During 2021, the market price of the common shares averaged $70 per share. Required: Compute Berclair's basic and diluted earnings per share for the year ended December 31, 2021. (Enter your answers in millions (i.e., 10,000,000 should be entered as 10). Do not round intermediate calculations.)
Business
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

Earnings Per share = $0.83

Diluted Earnings per share = $0.71

Explanation:

Basic Earnings per share is how much each common stock share earns in profits and Diluted Earnings includes the options and bonds in its calculations for outstanding shares

formulas

Earnings Per share = (net income - Preferred stock dividends)/ outstanding number of shares

                              = $150/180

                              = $0.83

Diluted Earnings per share = (net income - Preferred stock dividends)/ outstanding number of shares

                                             = $150/210

                                             = $0.71

Outstanding number of shares  in millions

opening                                                       200

minus treasury stock                                 - 24

issued stock                                                 4

Basic outstanding shares                       = 180 shares

plus  share Options                                    30

Diluted shares                                           210

                 

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Q 5.36: Badger Enterprises purchased aluminum from JG Metals. When Badger Enterprises recorded this transaction, they made entri
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Answer: periodic inventory system

Explanation:

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3 years ago
The financial statement that summarizes the profit-generating activities of a company during a particular period of time is the_
BabaBlast [244]

Answer:

Income statement.

Explanation:

The financial statement that summarizes the profit-generating activities of a company during a particular period of time is the Income statement.

Income statement is one of the most important financial statement used to analyze the financial performance of the company. It show the revenue and expense of the company in the particular period of time. It help the management to understand the profitablity of the company during specified period of time. The other two important financial statement are Balance sheet and statement of cash flow.

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2 years ago
A company accepts a customer's order on November 30 and immediately delivers the goods to the customer. On December 1, the compa
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Answer:

A) November 30

Explanation:

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Revenue is said to be earned when the obligation of the delivery of service or goods sold has been met.

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6 0
3 years ago
A metal sphere of radius 15 cm has a net charge of 3.0 $ 10#8 C. (a) What is the electric field at the sphere’s surface? (b) If
denis-greek [22]

Answer:

E = 1.20 × 10^{4} N/C

V = 1800 V

x = 0.058 m

Explanation:

given data

radius = 15 cm

net charge = 3 × 10^{-8} C

electric potential decreased = 500 V

solution

we get here electric field at the sphere’s surface that is

electric field at the sphere’s surface E  =  \frac{q}{4\pi \epsilon _o R^2}   ............1

put here value

electric field at the sphere’s surface E  = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15^2}    

E = 1.20 × 10^{4} N/C

and

potential on surface of sphere is

V =  \frac{q}{4\pi \epsilon _o R} ................2

V = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15}  

V = 1800 V

and

now we get distance that is x

and we know here

ΔV = V(x) - V   ..............3

substitute here value

-500V = \frac{q}{4\pi \epsilon _o } \times (\frac{1}{R+x} - \frac{1}{R})

-500 V = {3\times 10^{-8}\times 8.99\times 10^9} \times (\frac{1}{0.15+x} - \frac{1}{0.15})

solve it we get x

x = 0.058 m

3 0
3 years ago
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