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inessss [21]
4 years ago
15

What is the answer math problem ___-30-7 1/4= 21 2/3

Mathematics
1 answer:
Ronch [10]4 years ago
8 0
Common denominator would be 12
__-30 - 7 3/12= 21 8/12
         +7 3/12    +7 3/12
__________________
         __-30=28 11/12
             +30       +30
         ___=58 11/12

answer is 58 11/12
            
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Help now!!! Due at midnight
jasenka [17]

Answer:

20

Step-by-step explanation:

the answer is 20 hope this helps

6 0
3 years ago
Read 2 more answers
Can someone please help me with this! I'll do my best to give a lot of points for it!
Triss [41]
1. By combining like terms
2. Same variable = same term, so you can combine them
3. Because 2y - y = 1y , and 1y is the same as y because a y is one y (obviously)
4. 1/2 + 1/2 = 1. A half an x and a half an x makes one whole x, therefore, x
5. No. You solve them like you would a normal equation with like terms. So it would be 3z^2

Hopefully these are right, I’m a bit rusty!
6. 4x
7. 3y
8. y - 4.5
9. 3.5x + 2
10. 4y + 2
11. 7x
12. 2.2w - 0.5
13. 23b + 6.6
14. 3.75x + 1.5
15. 0.8x + 2.1
Good luck, I hope this helped
8 0
3 years ago
Solve for x help thx
valentinak56 [21]
X = 8
because 8 x 2 = 16
16 - 9 = 5
5 x 3 = 15
5 0
3 years ago
Read 2 more answers
What is the area of a sheet of binder paper? (Binder paper is 8 1/2 inches by 11 inches.)
11Alexandr11 [23.1K]
Area of a rectangle is the product of length times width.  Thus, here we need the product of 8 1/2 inches by 11 inches.

One way of doing this follows:            8.5
                                                         8.5
                                                       ----------         
                                                         93.5 square inches

Rounding up, this comes out to 94 square inches.

Alternatively:     17             187
                         ---- * 11 = ------- = 93.5 square inches; rounded, that's 94.
                           2                 2
3 0
3 years ago
If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn
mash [69]

Let a=\tan A and b=\sin A. Then

m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab

\implies m^2-n^2=4\tan A\sin A

and

mn=(a+b)(a-b)=a^2-b^2

\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}

The expression under the square root can be rewritten as

\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)

Recall that

\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A

so that

\tan^2A-\sin^2A=\sin^2A\tan^2A

and assuming \sin A>0 and \tan A>0, we end up with

4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A

so that

m^2-n^2=4\sqrt{mn}

as required.

5 0
3 years ago
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