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4 years ago

What is 40 over 72 in simplest form

Mathematics

1 answer:

MaRussiya [10]4 years ago

6 0

5/9 divide top and botom by 9

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The altitude of an equilateral triangle is 5 cm. what is the length of a side of the triangle?

Grace [21]

Answer:

The length side of the triangle is $\frac{10\sqrt{3}}{3}\ cm$

Step-by-step explanation:

we know that

The equilateral triangle has three equal sides and three equal internal angles of measure of 60 degrees each.

Let

b------> the length side of the equilateral triangle

Applying Pythagoras theorem

$b^{2}=(b/2)^{2}+5^{2}\\\\ b^{2}-(b/2)^{2}=25\\\\ (3/4)b^{2}=25\\ \\b^{2} =25*4/3\\ \\b=\frac{10}{\sqrt{3}}\ cm\\ \\b=\frac{10\sqrt{3}}{3}\ cm$

3 0

4 years ago

Slope of 0 3 and 4 1

attashe74 [19]

Answer:

m = $\frac{-1}{2}$

Step-by-step explanation:

The slope of (0,3) (4,1) =

$\frac{-1}{2}$

Hope this helps :)

6 0

3 years ago

Read 2 more answers

A line passing (a,3) and (5,5) is perpendicular to a line passing through (0,0) and (1,a) Find the value of a.

vodka [1.7K]

Answer:

a = -5

Step-by-step explanation:

(5 - 3)/(5 - a)

2/(5 - a)

perpendicular of 2/(5 - a) = -(5 - a)/2

(a - 0)/(1 - 0) = -(5 - a)/2

a/1 = -(5 - a)/2

2a = -5 + a

a = -5

6 0

4 years ago

Please help me out - I’m confused

Arte-miy333 [17]

Step-by-step explanation:

espero te sirva. Hope it helps you

6 0

3 years ago

After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos

igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

$d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}$

and we found the distance PQ and QA

; $d_{PQ}=\sqrt{125}$ , $d_{QA}=12$

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0

3 years ago