Let 
be the set of all students in the <u>c</u>lassroom.
Let 
and 
be the sets of students that pass <u>p</u>hysics and <u>m</u>ath, respectively.
We're given
i. We can split up into subsets of students that pass both physics and math 
and those that pass only physics 
. These sets are disjoint, so
ii. 9 students fails both subjects, so we find
By the inclusion/exclusion principle,
Using the result from part (i), we have
and so the probability of selecting a student from this set is
Answer:
The distance between the two stars in miles is 5.292 * 10^10 miles
Step-by-step explanation:
Here, we want to make a conversion from light year to miles
To make this conversion, we simply are going to multiply the light year by the miles
Mathematically, we have this as;
9 * 10^-3 * 5.88 * 10^12
= 52.92 * 10^9
= 5.292 * 10^10 miles
D. 45 and can you answer my history please ASAP
Answer:
26$ Per ticket
missing number is 156$
Step-by-step explanation:
Find how much each ticket is by dividing 78 by 3 which is 26 the multiply 26 and 6 to find the missing number hope this helped :)
