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muminat
3 years ago
11

eric had 143 baseball cards. his uncle gave him a number more. then eric gave his friend 26 cards. he has 184 cards now. how man

y cards did Eric's uncle give him?
Mathematics
2 answers:
monitta3 years ago
8 0

<u>Answer:</u>

Eric's uncle gave him 67 cards.

<u>Step-by-step explanation:</u>

We know that:

the number of baseball cards Eric had earlier = 143,

the number of cards Eric's uncle gave him = x,

the number of cards Eric gave to his friends = 26, and

the number of cards Eric is left with = 184

So before giving 26 cards to his friend, Eric had = 184 + 26 = 210

and initially he had 143 cards.

Therefore, his uncle gave him = 210 - 143 = 67 cards.

Fiesta28 [93]3 years ago
7 0

Answer: He has 67 cards now


Step-by-step explanation:


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Ms. Fitzgerald had 2 1 /4 gallons of fruit punch. She served 3 /8 gallon of the fruit punch
Luda [366]

Answer:

1 7/8

Step-by-step explanation:

1/4=2/8

2+2/8-3/8= 1 7/8

8 0
2 years ago
A Packaging Company produces boxes out of cardboard and has a specified weight of 16 oz. A random sample of 36 boxes yielded a s
user100 [1]

Answer:

The margin of error is of 0.73 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{1.7}{\sqrt{36}} = 0.73

The margin of error is of 0.73 oz.

The lower end of the interval is the sample mean subtracted by M. So it is 15.3 - 0.73 = 14.57 oz.

The upper end of the interval is the sample mean added to M. So it is 15.3 + 0.73 = 16.03 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

4 0
2 years ago
Researchers studying the acquisition of pronunciation often compare measurements made on the recorded speech of adults and child
dolphi86 [110]

Answer:

(A) The additional information that is needed to confirm about the conditions for this test have been met is ‘Population is approximately normal.

(B) The test statistic = 1.9965

(C1) P-value = 0.0556

(C2) There is no significant difference between mean VOT for children and adults.

D1) It is possible to make type II error.

(D2) There should be a difference in the VOT of adults and children.

Step-by-step explanation:

Let na be the number of adults = 20

xa mean VOT for adults = 88.17

sa standard deviatiation of VOT for adults = 24.74

Let nc be the number of children = 10

xc mean VOT for children =60.67

sc standard deviatiation of VOT for children = 39.89

(A) From the information the population variances are unknown and the two sample are assumed to be independent and the sample the sample size are smaller that is (n<30).

This indicates that the additional information that is required for the conditions of the test to be satisfied is 'distribution of the population'. the addition assumption to be made is, that the population distribution is normal.

(b) Calculating the test statistics using the formula;

t = (xa -xc)/SE - d

where SE = standard deviation , d= hypothesized difference = 0

But SE = √sa²/na +sc²/nc

           = √24.74 ²/20 + 39.89²/10

           = √189.72559

           = 13.774

Substituting into test statistics equation, we have

t = (xa -xc)/SE - d

  = (88.17 - 60.67/13.774

  = 1.9965

Therefore the test statistic is 1.9965

(c) Calculating the p-value, we have;

Degree of freedom = na + nc -2

                                 = 10+ 20 -2

                                 = 28

The p-value for t=1.9965 at 28 degrees of freedom and 0.05 level of significance is 0.0556.

The p-value 0.0556 is greater than given level of significance 0.05 hence we fail to reject the null hypothesis and conclude that there is no significant difference between mean VOT for children and adults.

(D1) From the information in part (C) the null hypothesis is not rejected.

Since the null hypothesis is not rejected, there might be a chance that not rejecting null hypothesis would be wrong. In this type of situation the error that can occur would be type II error.

(D2) The type of error describe in the context of this study is obtained by the concept of the type II error which tells that the null hypothesis is not rejected when it is actually false.

7 0
3 years ago
If neither a nor b are equal to zero, which answer most accurately describes the product of (a + bi)(a - bi)?
Scrat [10]

Answer:  the correct option is

(D) The imaginary part is zero.

Step-by-step explanation:  Given that neither a nor b are  equal to zero.

We are to select the correct statement that accurately describes the following product :

P=(a+bi)(a-bi)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We will be using the following formula :

(x+y)(x-y)=x^2-y^2.

From product (i), we get

P\\\\=(a+bi)(a-bi)\\\\=a^2-(bi)^2\\\\=a^2-b^2i^2\\\\=a^2-b^2\times (-1)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }i^2=-1]\\\\=a^2+b^2.

So, there is no imaginary part in the given product.

Thus, the correct option is

(D) The imaginary part is zero.

3 0
3 years ago
Describe this number line and the numbers and fractions shown.
Mariana [72]

Answer:

The number line goes from negative two to two.

The numbers shown by the number line (-2, -1, 0, 1 and 2) are all integers.

Between each pair of numbers, there are 4 equal segments, each one of 1/4 = 0.25 units length. Therefore we can locate, for example, 1.25, 0.5 and -0.75 at the number line.

6 0
3 years ago
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