Question

What is the range of y=sec^-1(x)?

Answer 1

Answer:

Range is [0, π/2) ∪ [π/2, π)

Step-by-step explanation:

For the given function $y=sec^{-1}x$ if we draw a graph we find that it's discontinuous at x = -1 and 1.

Therefore domain of the function will be = (-∞, -1]∪[1, ∞)

and the range of the function will be [0, π/2) ∪ (π/2, π].

Answer 2

Assuming that the x is not part of the ^-1 the range would be 

[0,π/2) U (π/2,π]