I only got one: A and B but I thinks it’s more than one. Please help

Mathematics

1 answer:

Agata [3.3K]3 years ago

3 0

It’s A and B and then D and F

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It is given that in △ABC, AD ⊥ BC. Using the definition of sine with angle C in △ACD results in sin(C) = . Using the multiplicat

amid [387]

We see here in the diagram that the base is a. We know this because the height is perpendicular to it. We also know the height is bsin(C) which, when replace h for bsin(C) and a for the base, we get A=absin(C), which is the second option.

7 0

2 years ago

Read 2 more answers

$12,800 15% is taken out what's the answer

Anuta_ua [19.1K]

Answer:

$10,880

Step-by-step explanation:

15% = 15 ÷ 100 = 0.15

So 15% of 12800 = 0.15 x 12800 = 1920

Therefore, 12800 - 1920 = 10880

12800 x (1 - 0.15) = 10880

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2 years ago

given the points a (-1,2) and (7,14), find the coordinates of the point p on directed line segment ab that partitions ab in the

Vinvika [58]

Check the picture below.

$\bf \left. \qquad \right.\textit{internal division of a line segment}
\\\\\\
a(-1,2)\qquad b(7,14)\qquad
\qquad 1:3
\\\\\\
\cfrac{aP}{Pb} = \cfrac{1}{3}\implies \cfrac{a}{b} = \cfrac{1}{3}\implies 3a=1b\implies 3(-1,2)=1(7,14)
\\\\
-------------------------------\\\\
{ P=\left(\cfrac{\textit{sum of "x" values}}{r1+r2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{r1+r2}\right)}$

$\bf -------------------------------\\\\
P=\left(\cfrac{(3\cdot -1)+(1\cdot 7)}{1+3}\quad ,\quad \cfrac{(3\cdot 2)+(1\cdot 14)}{1+3}\right)
\\\\\\
P=\left( \cfrac{-3+7}{4}~,~\cfrac{6+14}{4} \right)$