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kap26 [50]
3 years ago
13

A minigolf ball is on a perfectly horizontal surface, x = 2 m away from the center of the hole. There is a small obstacle in the

way, so the ball cannot simply roll to the hole –it must go up in the air. The player is able to shoot with an initial speed v0 = 7 m/s. The ball can be launched at TWO possible angles with the horizontal for the ball to get in the hole. We want you to find these two angles.
Mathematics
1 answer:
nika2105 [10]3 years ago
6 0
<h3>Answer:</h3><h3>Two possible smallest and largest angles are 11.78° and 78.22°.</h3>

Step-by-step explanation:

Minigolf ball will follow a trajectory to get into the hole.

Since range of a trajectory is calculated by the formula,

R=\frac{u^{2}sin2\theta}{g}

Where u = initial speed of the ball

θ = angle between the hole and direction in which the ball has been projected

g = gravitational pull

Now we plug in the values in the formula,

2=\frac{7^{2}sin(2\theta)}{9.8}

sin2θ = \frac{2\times 9.8}{49}

2θ = sin^{-1}(0.4)

2θ = 23.57° or 156.43°

θ = 11.78° or 78.22°

Hence two possible smallest and largest angles are 11.78° and 78.22°.

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Step-by-step explanation:

The triangle inequality theorem states that the sum of any two sides of a triangle must be greater than the third side, for it to form a triangle. So, we can set up 3 equations, x + 5.8 > 6, 5.8 + 6 > x, and x + 6 > 5.8. This solves out to x > 0.2, x < 11.8, and x > -0.2. We can disregard that last one, because a side can't be negative. Therefore, we know the possible range of values for x.

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Answer:  \sqrt{r^2+s^2

=====================================================

Reason:

Plot the points (0,0) and (r,s). You can place (r,s) anywhere you want.

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The horizontal leg has a length of r-0 = r units, while the vertical leg will be 's' units.

Check out the diagram below.

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