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Nonamiya [84]
3 years ago
5

On Chris's birthday in 1992, he was half the age of his brother Joseph. On Chris' birthday in 1998, he was two-thirds the age of

Joseph. How old will Chris be on his birthday in 2018?
Mathematics
1 answer:
aev [14]3 years ago
7 0
Suppose in 1992 Chris was x years old, his brother was then 2x years old.
6 years later in 1998, Chris is (x+6) years old, his brother is (2x+6), 
(x+6)=(2/3)(2x+6)
x+6=(4/3)x+4
(4/3)x-x=6-4
(1/3)x=3
x=6
in 1992, Chris was 6, so in 2018 he will be 6+(2018-1992)=32 years old. 
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Answer:

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Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

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step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

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Convert to minutes

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step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

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\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

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