Answer:
Step-by-step explanation:
step 1
Find the measure of arc PK
we know that
The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.
Let
x------> the measure of arc IV
y ------> the measure of arc PK
substitute the values and solve for y
The measure of arc PK is 
step 2
Find the measure of angle VPL
we know that
The inscribed angle measures half that of the arc comprising
Let
z------> the measure of arc VK
y ------> the measure of arc PK
substitute the values
Answer:
New value =
39 - Percentage decrease =
39 - (3% × 39) =
39 - 3% × 39 =
(1 - 3%) × 39 =
(100% - 3%) × 39 =
97% × 39 =
97 ÷ 100 × 39 =
97 × 39 ÷ 100 =
3,783 ÷ 100 =
37.83
Step-by-step explanation:
<u>Answer:</u>
<u>Step-by-step explanation:</u>
32a^3 + 12a^2
To factorize this, start by taking the common variable out. As we have two powers for the same variable a, we can take the smaller power of a as a common to get like shown below:
32a^3 + 12a^2
a^2 (32a + 12)
Now when you have taken the variable as a common, try and take out a common number from the coefficient of a as well:
a^2 (32a + 12)
4a^2 (8a + 3)
So, the fully factored form of 32a^3 + 12a^2 is 4a^2 (8a + 3).
Answer:
D
Step-by-step explanation:
Multiply by 3
4 x 3 = 12
9 x 3 = 27
1.)
Velocity is in m/s, and acceleration is in m/s^2 like you said. Because of this, we can calculate this by dividing the speed by the time it took to get to that speed.
(20 meters/second) / 10 seconds = 2 meters/ second^2
2.)
Same thing with the first one.
(100 meters/second) / 4 seconds = 25 meters / seconds^2
