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Answer:
The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as
* (morality of solution)
and
are the freezing points of the pure solvent (water, 0°C) and
= freezing point depression constant of water. Therefore,
*(0.859 m)
=====> (0°C) – (3.00°C) =
=====> -3.00°C =
Ignore the negative sign (since is positive) and get
= (3.00°C) / (0.859 m) = 3.492°C/m
The freezing point depression constant of the solvent is 3.5°C kg/mole
3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).
Step-by-step explanation:
slope = x factor = - 5/2
Perpendicular slopes must be opposite reciprocals of each other: m1 * m2 = –1
New slope = 2/5 = m
y = mx + b
from the point given y = 2 | x = -4
2 = (2/5 × -4 ) + b
2 = - 1.6 + b
b = 3.6
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