Answer:
Step-by-step explanation:
The equation of a line in point-slope form is
where y1 and x1 are 2 known points, and m is the slope of the line. So simply just fill in the blanks.
y is a variable so it is left alone (since there is no subscript).
y1 we are told is 1.
m we are told is -3 (the slope)
x is a variable so it is left alone (since there is no subscript).
x1 we are told is 6.
Answer:
9,591
Step-by-step explanation:
Porque asi lo dice la calculadora
Answer: The answer is your bad, you shouldnt be "answering" questions with " sorry i need points"
Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
The coordinates of r is ( 4, -1 )
