3 years ago

Find the 14th term of the geometric sequence 6, -18,54, ...

Mathematics

2 answers:

andrey2020 [161]3 years ago

8 0

Step-by-step explanation:

first term (t1) = 6 (a)

Second term (t2) = - 18

Common ratio (r) = t2/ t1 = - 18 / 6 = -3

Now

14th term (t14)

$a {r}^{14 - 1}$

$6 \times ( - 3)^{13}$

= 6 X - 1594323

= 9565938

mafiozo [28]3 years ago

4 0

Answer:

- 9565938

Step-by-step explanation:

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