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Andrej [43]
3 years ago
8

Amazon uses a customer profiling system whenever a customer visits its website. Using this system, Amazon can offer products tai

lored to that particular customer's profile and buying pattern. What is Amazon using to achieve this competitive advantage?A. Rivalry.
B. Buyer power.
C. Product differentiation.
D. Substitute product.
Computers and Technology
1 answer:
NemiM [27]3 years ago
4 0

Answer:

C. Product differentiation

Explanation:

-Rivalry refers to the competition between people or organizations when they have the same goal.

-Buyer power refers to the situation in which customers are able to have influence on things like quality and prices of the products offered by companies.

-Product differentiation refers to trying to differentiate a product or service from its competition to make it more attractive for the customer.

-Substitute product is a good that can be used instead of another one.

According to this, Amazon is using product differentiation to achieve this competitive advantage as it is offering products tailored to a particular customer which is an effort to make the product distinguish from the similar ones and get the customer to buy it.

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Write a C program to prform simple C aritlimetic calculations. The user is to enter a simple expression(integer operaior integer
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Answer:

Here is the C program:

#include <stdio.h>  //to use input output functions

//functions prototype

unsigned int mod(unsigned int a, unsigned int b);  

unsigned int mul(unsigned int a, unsigned int b);  

unsigned int sub( unsigned int a,unsigned int b);

float divide(unsigned int a,unsigned int b);  

unsigned int add( unsigned int a,unsigned int b);  

int main()  {  //start of main method

unsigned int a, b;   //declare variables to store the operands

char d;  //declare variable to store the operator

printf("Enter an operator:  ");   //prompts user to enter an operator

scanf("%c",&d);  //reads the operator from use

getchar();  //gets a character

while (d!='q')   { //keeps iterating until user enters q to quit

printf("Enter 1st operand: ");   //prompts user to enter first operand

scanf("%d",&a);   //reads first operand from user

getchar();  //reads character

printf("Enter 2nd operand: ");   //prompts user to enter second operand

scanf("%d",&b);   //reads second operand from user

getchar();  

if (d=='%')  {   //if the character of operator is a mod

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

mod(a,b);  }  //displays computed modulo of two input operands

if (d=='*')   //if the input character is for multiplication operator

{printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

mul(a,b); }  //displays computed multiplication

if (d=='+')  {  //if the input character is for addition operator

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = "); // displays =

add(a,b);  }   //displays computed addition

if (d=='/')  {  //if the input character is for division operator

printf("%d",a); // prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

divide(a,b);  }   //displays computed division

if (d=='-')  {  //if the input character is for subtraction operator

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b); // displays operand 2

printf(" = ");  //displays =

sub(a,b);  }  //displays computed subtraction

printf("Enter an operator: ");   //asks again to enter an operator

scanf("%c",&d);  //reads operator from user

getchar();  }  }   //gets character

unsigned int mod( unsigned int a, unsigned int b){  //function to compute modulo of two integers with no sign

     int c = a%b;  //computes mod

    printf("%d",c);  }  //displays mod result

unsigned int add(unsigned int a, unsigned int b){     // function to compute addition of two integers

    int c = a+b; //computes addition

    printf("%d\n",c);  } //displays result of addition

unsigned int mul(unsigned int a, unsigned int b){       //function to compute multiplication of two integers

    int c = a*b;  //multiplies two integers

   printf("%d\n",c); }  //displays result of multiplication

float divide(unsigned int a, unsigned int b){   //function to compute division of two integers

    float c = a/b;  //divides two integers and stores result in floating point variable c

    printf("%f\n",c);  } //displays result of division

unsigned int sub(unsigned int a, unsigned int b){       //function to compute subtraction of two integers

    int c = a-b;  //subtracts two integers

    printf("%d\n",c);  }  //displays result of subtraction

Explanation:

The program is well explained in the comments mentioned with each line of the program. The program uses while loop that keeps asking user to select an operator and two operands to perform arithmetic calculations. The if conditions are used to check what arithmetic calculation is to be performed based on user choice of operand and calls the relevant function to perform calculation. There are five functions that perform addition, modulo, subtraction, division and multiplication and display the result of computation. The screenshot of output is attached.

4 0
3 years ago
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