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2 years ago

How does naming affect a variable’s creation and use?

Computers and Technology

1 answer:

Evgen [1.6K]2 years ago

4 0

Answer:

Each variable is named so it is clear which variable is being used at any time. It is important to use meaningful names for variables: ... The name given to each variable is up to the programmer, but ideally a variable name should have meaning, ie it should reflect the value that it is holding.

Variables make code more than a static set of instructions. They allow logic to occur, enabling developers to measure time, analyze data, and customize the program to the user. Variables are so important to the code that they deserve a good name that accurately describes their purpose

Explanation:

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Computer system with a 32-bit logical address and 4k-byte page size. assume that each entry of a page table consists of 4bytes.

Annette [7]

The number of bits in the physical address is 26 bits. The number of entries in a page table is $\mathbf{2^{20}}$ entries. The size of the page table in a one-level paging scheme is 4MB.

<h3>
What is paging in Operating System?</h3>

Paging is a storage method used in operating systems to recover activities as pages from secondary storage and place them in primary memory. The basic purpose of pagination is to separate each procedure into pages.

We are given the following parameters:

32-bit logical address
Page size = 4 KB = $\mathbf{2^{12} \ bytes }$
Size of each Page table entry = 4 bytes

Suppose the system supports physical memory size = 64 MB = $\mathbf{2^{26} \ bytes}$

Thus, the number of bits in the physical address is computed as:

= $\mathbf{log_2 \{Physical-memory-size\}}$

$=\mathbf{log_2(2^{26})}}$

= 26 bits

The number of entries in a page table = logical address space size/page size

The number of entries in a page table $\mathbf{= \dfrac{2^{32}}{2^{12}}}$

$\mathbf{=2^{20}}$ entries

In a one-level paging scheme, the size of the table is:

= entire no. of page entries × page table size

= $\mathbf{2^{20}\times 4 \ bytes}$

= 4 MB

suppose that this system supports up to 2^30 bytes of physical memory.

The size of the page table will be the same as 4 MB due to the fact that the number of entries, as well as, the page table entry size is the same.

Since the size of the page table surpasses that of a single page. A page cannot include a whole page table. Therefore, the page table must be broken into parts to fit onto numerous pages, and an additional level of the page table is required to access this page table.

This is called the Multi-Level Paging system.

Therefore, we can conclude that the number of bits in the physical address is 26 bits, the number of entries in a page table is $\mathbf{2^{20}}$ entries, and the size of the page table in a one-level paging scheme is 4MB.

Learn more about Paging in Operating System here:

brainly.com/question/17004314

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4 0

2 years ago

Assume that you have an ArrayList variable named a containing 4 elements, and an object named element that is the correct type t

jonny [76]

Answer:

Option (4) is the correct answer.

Explanation:

In Java programming language ,array collection starts from 0 index location and ends in a size-1 index location. So to access the last elements the user needs to use a[Size-1] statement. so to modify the value of the last location of the array the user needs to use "a[size-1]= element;".

But when the user wants to add some new value to the end of the array list collection then he needs to use the statement--

a.add(element); //where add is a function, element is a value and a is a array list object.

Another option is invalid because--

Option 1 is not the correct because "a[3]=element;" modify the value of the 3rd element of the array.
Option 2 gives a compile-time error because add functions bracts are not closed.
Option 3 gives the error because a[4] gives the location of the 5th element of the array but the above question says that a is defined with 4 elements.

7 0

3 years ago

How does Technology impact any profession or occupation?

Brrunno [24]

Technology can create or dimish occupations.

Technology can also make the job easier

8 0

3 years ago

What are the two ways to print a document?

guajiro [1.7K]

Answer:

ctrl+p or find the print button on the page

5 0

3 years ago

Name two primary goals of quality assurance and control programs:

bulgar [2K]

Answer:

The two main goals are to reach CMM level 5, and when the company can be termed as optimized.

The second goal is to minimize the bugs at the current level as well. And this is important, as improvement is one thing, and ensuring you are correct at the current time is another, and which is essential for survival. And you can think of improvement only if you survive.

Explanation:

The dream of all companies is to become Optimized. And they always try to reach CMM level 5, such that they can serve their clients in the best possible manner. And it is the quality assurance team that keeps an eye on the working of the company and keeps on giving their feedback so that the team can provide better service to the clients in the future, and probably reach the CMMI level 5.

The control program makes the operating system better through the development of an environment in which one can run various other programs. And it, in general, formulates the graphical interface and leverage you to run various programs at one time in various windows. And the control programs are also being known as the operating environment.

5 0

3 years ago