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FrozenT [24]
4 years ago
6

a man and a daughter stand on a scale they weigh 90kg. The man gets back on with his cat together they weigh 70kg. The daughter

and the cat weigh 40kg together. How much do the man, his daughter, and their cat weigh on their own?
Mathematics
2 answers:
Alexeev081 [22]4 years ago
8 0
The man is 60kg and the daughter 30kg  because 60+30=90. The cat has to weigh 10kg because the man's weight 60kg plus the cat's weight 10kg is 70kg. Also because the daughter's weight 30kg plus the cat's weight 10kg is 40kg.
Marta_Voda [28]4 years ago
3 0
The man weighs 60kg. The daughter weighs 30kg. The cat weighs 10kg.
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Answer:

The answer to your question is 43.8 mL of acid.

Step-by-step explanation:

Data

Total volume = 362 ml

12.1 % is acid

The Volume of acid = ?

Process

1.- Use the rule of three and cross multiplication to solve this problem.

               362 ml ------------------- 100%

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                    x = (12.1 x 362) / 100

                    x = 4380.2 / 100

                    x = 43.802 ml

2.- Round your answer to the nearest tenth.

                        43.802   only consider the first decimal

                        43.8 mL

3.- Conclusion

    A 12.1% solution of acid has 43.8 mL of acid.

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In parallelogram LMNP if PQ=21 find QM.
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Answer:

QM = 21

Step-by-step explanation:

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maks197457 [2]

Answer:

The missing value = 23\frac{1}{24}

Step-by-step explanation:

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To find - Explain (in words) what you would do to find the missing value in

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Proof -

Let the missing number = x

So, the equation becomes x + 59\frac{5}{8} = 82\frac{2}{3}

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