What is the general form of the equation of the given circle with center A
1 answer:
Your answer would be option C. x² + y² + 6x - 24y + 128 = 0.
This is because the formula for the equation of a circle is (x - [x coordinate])² + (y - [y coordinate])² = radius², so you have to substitute in the coordinates and the radius, and then expand and simplify. I have done this in paper as it is easier to write than type, but let me know if you would like me to explain any part of it.
I hope this helps!
This is because the formula for the equation of a circle is (x - [x coordinate])² + (y - [y coordinate])² = radius², so you have to substitute in the coordinates and the radius, and then expand and simplify. I have done this in paper as it is easier to write than type, but let me know if you would like me to explain any part of it.
I hope this helps!
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y = -9
Ok so to write the equation of the line you will need the slope and y-intercept. Since we are given two-point we can easily find the slope by using this equation for slope formula:
So now that we have our equation we can just plug in the numbers:
After subtracting you should get:
0/8
Since zero is in the numerator and you can't divide zero by anything, the slope is 0. We still need the y-intercept for the equation however since the slope is 0 there is no need to put anything else.
Then to find the y-intercept all you have to do is plug in one of the coordinatines into the slope equation to solve, for example, using the point (5,-9):
B is the variable for the y-intercept. Also notice how I put 0 as our slope into the equation. Now all you have to do is solve for b. Which you would get b = -9. Since you have your slope and your y-intercept now you just write out your equatoin for the line which is:
y = 0x - 9
**Just write it as
y = -9