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podryga [215]
3 years ago
13

How many possible 10-digit phone numbers with the area code 617 are there? (any decimal digit can be the digit of a phone number

. For instance the number 617−000−0000 is a possible phone number)
Mathematics
1 answer:
V125BC [204]3 years ago
7 0
If all digits are possible and we are restricted to the 617 area code, then there are:

10^7 possible numbers  

Because each digit can have 10 possible values from 0 through 9, you get

10*10*10*10*10*10*10 which is just 10^7

10,000,000  (ten million)
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From 1997 - 2001 the number n (in millions) of black-and-white TV S sold in the U.S. Can be modeled by n = 26.8 * (0.85) ^ t whe
Alexandra [31]

Question

a) What is the decay factor?

b) What is the percent decrease?

c) Estimate the number of black and white TV's  sold in 1999.

Answer:

a. Decay factor = 0.85

b. Percent decrease = 15%

c. 19.363  million TVs were sold

Step-by-step explanation:

Given

n = 26.8(0.85)^t

Solving (a): The decay factor

An exponential function has the form

y = ab^x

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b = decay\ factor\ or\ growth\ factor

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b = 0.85

Solving (b): Percentage decrease:

Percentage decrease P is calculated as follows:

P = 1 - b

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P = 1 - 0.85

P = 0.15

Convert to percentage

P = 0.15*100\%

P = 15\%

Solving (c): TVs sold in 1999

First, we need to determine the value of t for 1999

In 1997, t= 0

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In 1999, t= 2

So, we substitute 2 for t in: n = 26.8(0.85)^t

n = 26.8(0.85)^2

n = 26.8*0.7225

n = 19.363

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Correct answer choice is :


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