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faltersainse [42]
3 years ago
9

Find the time it would take to triple an initial deposit of $2,000 at an interest rate of 8%, compounded semi-annually

Mathematics
1 answer:
Mademuasel [1]3 years ago
3 0
It’s is 250 I hope I help have a nice night
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k is a an integer for which 1/2^1-k, 1/8. What is the value of k? 1/2^1-k must be equal to 1/8 if i read the question right.
svetlana [45]

Answer:

k = -2

Step-by-step explanation:

If \frac12^{1-k}=\frac18

Then

\frac1{2^{1-k}}=\frac18=\frac1{2^3}

So

1-k = 3

From this follows k = -2

3 0
3 years ago
Giving out 100 POINTS FOR THIS QUESTION!! Please don’t write nfoenwownw or something like that for the points!! I really need he
Paha777 [63]

Answer:

C) (1,0), and (-3,0)

Step-by-step explanation:

The parabola intercepts the x axis at points (1,0) and (-3,0).

8 0
2 years ago
Read 2 more answers
Pls hurry I need the answer
katrin [286]
<h3>Answer:  48 degrees</h3>

=============================================

Work Shown:

Apply the law of cosines

a^2 = b^2 + c^2 - 2*b*c*cos(A)

10^2 = 13^2 + 11^2 - 2*13*11*cos(A)

100 = 290 - 286*cos(A)

100-290 = -286*cos(A)

-190 = -286*cos(A)

190 = 286*cos(A)

286*cos(A) = 190

cos(A) = 190/286

A = arccos(190/286)

A = 48.368620460647

A = 48

Make sure your calculator is in degree mode.

3 0
2 years ago
If f(x)= 10 sin(x) – 3 then f (30%) = ?
marissa [1.9K]

Answer:

The value of f(30) is equal to 2.

Step-by-step explanation:

The given expression is :

f(x)= 10 \sin(x) - 3

We need to find the value of f(30)

Put x = 30 in above expression.

So,

f(x)= 10 \sin(30) - 3\\\\=10\times \dfrac{1}{2}-3\\\\=5-3\\\\=2

Hence, the value of f(30) is equal to 2.

5 0
2 years ago
Compute the simple interest earned on a deposit of $5000 at 8.5% for 120 days
ICE Princess25 [194]
Keeping in mind that 120 days is not even a year, since there are 365 days in a year, exluding leap-years, then 120 days is really 120/365 year.

\bf ~~~~~~ \textit{Simple Interest Earned}&#10;\\\\&#10;I = Prt\qquad &#10;\begin{cases}&#10;I=\textit{interest earned}\\&#10;P=\textit{original amount deposited}\to& \$5000\\&#10;r=rate\to 8.5\%\to \frac{8.5}{100}\to &0.085\\&#10;t=years\to \frac{120}{365}\to &\frac{24}{73}&#10;\end{cases}&#10;\\\\\\&#10;I=(5000)(0.085)\left( \frac{24}{73} \right)\implies I \approx 139.72602739726
4 0
3 years ago
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