A password contains exactly 5 letters how many passwords are possible if letters cannot be used more than once?

2 answers:

6 0

The first letter can be any one of the 26 in the alphabet.
   For each one ...
The 2nd letter can be any one of the remaining 25.
   For each one ...
The 3rd letter can be any one of the remaining 24.
   For each one ...
The 4th letter can be any one of the remaining 23.
   For each one ...
The 5th letter can be any one of the remaining 22.

The total number of possibilities is

   (26 · 25 · 24 · 23 · 22) = 7,893,600 .

alexandr402 [8]3 years ago

3 0

3120 and 65,780 because they don't say the numbers twice. They're trying to trick you by saying letters.

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1. Draw the graph of f(x) = cos x for 0 I know how to construct the graph but I don’t know how to get the figures. Please help

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Answer:

Please refer to the attached figure.

Step-by-step explanation:

Given the function:

$f(x) =cosx \ where\ \{0^\circ\leq x\leq 360^\circ\}$

OR, the given function can also be written as:

$y = f(x) = cosx$

We know that graph of cosine is a wave.

and the range of cosine function is [-1, 1]

First of all, let us have a table of values at major values of x.

$x = 0, f(x) = 1\\x = 90, f(x) = 0\\x = 180, f(x) = -1\\x = 270, f(x) = 0\\x = 360, f(x) = 1$

So, the table of values for f(x) is:

$\begin{center}\begin{tabular}{ c c }x & cosx \\0 & 1 \\90 & 0\\180 & -1\\270 & 0\\360 & 1\\\end{tabular}\end{center}$

Let us mark these points on the xy coordinate axis where x axis represents value of<em> x </em>and y axis represents value of $f(x) = cosx$ and then join the points using a wave.