Angles are classified based on their measures.
<u>Classification of angles</u>
The following are the classification of angles
- Acute Angles
- Right Angles
- Obtuse Angles
- Straight lines
- Reflex Angles
The smallest angle is 0 degrees and the largest is 360 degrees.
When the measure of an angle is less than 90 degrees, such angle is an acute angle
When the measure of an angle is exactly 90 degrees, such angle is a right angle
Angles greater than 90 degrees, but less than 180 degree are obtuse angles, while angles that measure exactly 180 degrees are straight lines.
The last type of angle is the reflex angle, and it has a measure between 180 degrees and 360 degrees (exclusive)
<em>The question is incomplete, so I gave a general explanation</em>
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Answer:
Evey 12 days both of the trucks visit on the same day
Step-by-step explanation:
The LCM of 3 and 4 is 12, because 12 is the smallest number that 3 and 4 are both factors for.
<span>Calling the company that holds the car loan and asking them about other repayment options is the best tactic. This allows the loan holder to negotiate terms that would be acceptable to both sides, as well as showing that Angela is trying to make a good-faith effort to repay what she can. While it may increase the overall length of time that her payments require, it also shows that she is not going to outright default on the payments.</span>
Answer:
116−−√
110−−√
14√
18√
Step-by-step explanation:
Answer:
34.6 units
Step-by-step explanation:
The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.
The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).
Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:
Distance between point A(-6, 2) and point B(2, 6):

Let,





(nearest tenth)
Distance between B(2, 6) and C(7, 1):

Let,





(nearest tenth)
Distance between C(7, 1) and D(3, -5):

Let,





(nearest tenth)
Distance between D(3, -5) and A(-6, 2):

Let,





(nearest tenth)
Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units