Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
Answer:
The answer to your question is cost of 0.6 pound of candy $4.17
Step-by-step explanation:
Data
1 pound of candy = $6.95
only 0.6 pounds
final cost = ?
Process
1.- Use proportions to find the cost of 0.6 pounds of candy
1 pound of candy -------------- $6.95
0.6 pound of candy ---------- x
2.- Use cross multiplication
x = (0.6 x 6.95) / 1
3.- Simplification and result
x = $ 4.17
Answer:
-4
Step-by-step explanation:
Use PEMDAS
Answer:
$22.34
Step-by-step explanation:
24 pennies is .24 of a dollar
62 nickels will be: (62 x 5) / 100 = 3.10
55 dimes is 5.5
16 quarters will be 4.0
19 fifty-cents will be 9.5
Add them up to get $22.34 if I’m right.
Hope this helped.
Answer:
A 2-column table with 3 rows. Column 1 is labeled x with entries 12, 15, 18. Column 2 is labeled y with entries 6, 9, 12.
Step-by-step explanation:
A 2-column table with 3 rows. Column 1 is labeled x with entries 12, 15, 18. Column 2 is labeled y with entries 6, 9, 12.
