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laiz [17]
3 years ago
6

Simone used 2 1/3 kilograms of flour to bake a cake . She used 4/5 kilograms of flour more to bake a second cake. How much flour

did she use to bake the second cake?​
Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0

Answer:

3.13 kilograms used for the second cake

Step-by-step explanation:

because the fractions have different denominators you have to multiply the denominators together to figure out what to change them too. but instead you can just figure out what the decimal for each is. 1/3 is 0.33, and 4/5 is 0.80. all you do is add these together to get 1.13. so now all you do is add 2+1.13 to get 3.13.

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Question 31 (Essay Worth 5 points)
slega [8]

Answer:

-12

Step-by-step explanation:

ds/dt = d/dt ( 1-12 t)

ds/dt = -12

When t=2

ds/dt = -12

7 0
3 years ago
Multiples of 4 are even numbers
Vesna [10]

Answer:

The statement is true

Step-by-step explanation:

Multiples of 4 (until 40): 4 , 8 , 12 , 16 , 20 , 24 , 28 , 32 , 36 , 40

All of these are even numbers

4 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST TO BEST ANSWER! HELP ASAP!
Aleks [24]

Answer:

120 ft

Step-by-step explanation:

The distance the gravel covers is the total distance times the percentage that the gravel covers

We know the gravel covers 66 ft and the percentage is 55%

distance gravel = total distance * percentage

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66 = total distance *.55

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8 0
3 years ago
What is the simplification of (-2x+4) + 2(2x+1)
melomori [17]
(-2x+4)+2(2x+1)= -2(-x-3)
4 0
3 years ago
Juan bought 4 pounds of chocolate
Andru [333]

Answer:

Step-by-step explanation:

This is a system of equations.  The 2 equations are:

4c + 2p = 16

2c + 3p = 12

Let's get rid of the p's first.  Do this by multiplying the first equation by -3 and the second equation by 2 to get a new system that looks like this:

-12x - 6p = -48

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Now add to get

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That means that chocolate is $3 per pound.  Now sub that back in to either one of the original equations to get the price for peanuts:

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The price for peanuts is $2 per pound.

6 0
3 years ago
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