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Mathematics

2 answers:

skad [1K]3 years ago

7 0

real part of x(y)=4*2-(-9*5)=53 so 1 is x(y): real part of x(y)=

real part of 2x(y)=2*53=106 so 2 is 2x(y)

real part of -x+3y=-4+6=2 so 3 is -x + 3y

real part of 4x-y=16-2=14 so 4 is 4x - y

kenny6666 [7]3 years ago

4 0

1. 53 - 26i = x(y) cuz' real xy=4*2+9*5=53

2. 106 - 52i = 2x(y) cuz real 2xy=2*53=106

3. 2 - 32i = -x + 3y cuz real -x+3y=-4+3*2=6

4. 14 + 29i = 4x - y cuz real 4x-y=4*4-2=14

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Step-by-step explanation:

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3 years ago

The length of each side is quadrupled. How many times larger is the new area when compared to the original?

GaryK [48]

16 times larger is the new area when compared to the original.

Given that, the length of each side of the square is quadrupled.

We need to find how many times larger is the new area when compared to the original.

<h3>What is the area of a square?</h3>

A square is a closed two-dimensional shape with four equal sides and four equal angles. The four sides of the square form the four angles at the vertices. The sum of the total length of the sides of a square is its perimeter, and the total space occupied by the shape is the area of the square. The formula to calculate the area of a square is a².

Let the length of each side of the square be x.

Then the length of each side of the new square will be 4x.

Now, the area of the original square = x²

The area of the new square = (4x)² = 16x²

So, the new square = 16 × the original square

Therefore, 16 times larger is the new area when compared to the original.

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1 year ago

Which equation is equivalent to √x^2+81 = x+10

jeka57 [31]

Keywords:

<em>equation, operations, equivalent, binomial, square root </em>

For this case we have an equation in which we must apply operations to rewrite it in an equivalent way. We must start by raising both sides of the equation to the square. Thus, we eliminate the square root of the left side of equality and finally solve the binomial of the right side of equality.

So we have:

$\sqrt {x ^ 2 + 81} = x + 10\\(\sqrt {x ^ 2 + 81}) ^ 2 = (x + 10) ^ 2\\x ^ 2 + 81 = (x + 10) ^ 2$