The end point for a 192 degree angle is located in the third quadrant, where both x and y are negative, so both sin192, cos192 are negative.
9514 1404 393
Answer:
∠KXN and ∠QXT
Step-by-step explanation:
The measure of each angle is the difference of the scale values that the rays intercept. (The same scale needs to be used for each ray.) Of course, complementary angles have a sum of 90°.
Here, we'll refer to angle aXb as "ab".
NP = 95 -35 = 60
PQ = 35 -20 = 15 . . . not complementary to NP
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KN = 165 -95 = 70
QT = 20 -0 = 20 . . . complementary to KN ⇒ your answer
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JK = 180 -165 = 15
PQ = 35 -20 = 15 . . . not complementary to JK
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JK = 15
NK = KN = 70 . . . not complementary to JK
Answer:
What’s the freaking question G ??!?
The slope intercept form using the two points would be : y= 2x-13