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2 years ago

Write the equation of the perpendicular bisector of AB if A(-6, -4) and B (2,0).

Mathematics

1 answer:

valkas [14]2 years ago

4 0

Answer:

Step-by-step explanation:

Long way:

Find the midpoint (M) of AB, find the slope(m) of the line AB, then find the equation of the line through M with slope -1/m, which is the perpendicular bisector of AB.

Short way:

The perpendicular bisector of (x₁,y₁) and (x₂,y₂): 2(x₂-x₁)x + 2(y₂-y₁)y = x₂²-x₁²+y₂²-y₁².

Here this is 2(1-(-4))x + 2(6-4)y = 1²-(-4)²+6²-4² which is 10x + 4y = 5.

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5 out of 20 is what percent?

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Answer:

25%

Step-by-step explanation:

The first step is to divide 5 by 20 to get the answer in decimal form:

5 / 20 = 0.2500

Then, multiply the answer from the first step by one hundred to get the answer as a percentage:

0.2500 * 100 = 25.00%

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The value of the surface area (in square centimeters) of the cone is equal to the value of the volume (in cubic centimeters) of

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Answer:

The height of the cone is 10.9 cm

Step-by-step explanation:

step 1

Find the height of the cone

Applying the Pythagoras Theorem

$12^{2}=5^{2}+h^{2}$

$144=25+h^{2}$

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2 years ago

What is the length of the unknown side of the right triangle?

a_sh-v [17]

Answer:

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2 years ago

Given the general form of the sinusoidal function, y = AsinB(x - C) + D, match the following items.

Jet001 [13]

Answer:

$\Delta y = A$ (Amplitude) (Correct answer: 1)

$\omega = B$ (Angular frequency) (Correct answer: 2)

$x_{o} = C$ (Phase shift) (Correct answer: 3)

$y_{o} = D$ (Vertical shift) (Correct answer: 4)

$\frac{2\pi}{\omega} = \frac{2\pi}{B}$ (Period) (Correct answer: 5)

Step-by-step explanation:

The general form of a sinusoidal function is represented by the following characteristics:

$y = \Delta y \cdot \sin \omega\cdot (x- x_{o}) + y_{o}$ (1)

Where:

$\Delta y$ - Amplitude.

$\omega$ - Angular frequency.

$x_{o}$ - Phase shift.

$y_{o}$ - Vertical shift.

$x$ - Independent variable.

$y$ - Dependent variable.

In addition, we know that the period associated with the sinusoidal function ( $T$ ) is:

$T = \frac{2\pi}{\omega}$

By direct comparison, we get the following conclusions:

$\Delta y = A$ (Amplitude) (Correct answer: 1)

$\omega = B$ (Angular frequency) (Correct answer: 2)

$x_{o} = C$ (Phase shift) (Correct answer: 3)

$y_{o} = D$ (Vertical shift) (Correct answer: 4)

$\frac{2\pi}{\omega} = \frac{2\pi}{B}$ (Period) (Correct answer: 5)

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2 years ago