I’d help but the image isn’t working its all blurry on my end fam sorry
For this case we have the following fraction:
(1-cos ^ 2 (θ)) / (sin ^ 2 (θ))
We must take into account the following trigonometric identity:
cos ^ 2 (θ) + sin ^ 2 (θ) = 1
Therefore rewriting we have:
sin ^ 2 (θ) = 1 - cos ^ 2 (θ)
Substituting in the given fraction we have:
(1-cos ^ 2 (θ)) / (sin ^ 2 (θ))
= (sin ^ 2 (θ)) / (sin ^ 2 (θ))
= 1
Answer:
1
Answer:
3 I did the test to btw
Step-by-step explanation:
did the test
Answer: ![\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B3%7D%5B%5Cln%20%28x%2B1%29%2B%5Cln%28x-1%29%5D)
Step-by-step explanation:
Properties of logarithm :
The given expression in terms of Natural log : 
This will become 
[ By using Property (3)]
[
]
![=\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B3%7D%5B%5Cln%20%28x%2B1%29%2B%5Cln%28x-1%29%5D)
[ By using Property (1)]
Hence, the simplified expression becomes .
Answer:
The highest score is 94.
Step-by-step explanation:
Let the highest score be denoted by, <em>A</em>, the lowest score be, <em>B</em> and the middle score be <em>X</em>.
Then,
A + X + B = 87 × 3 = 261 ...(i)
X + B = 83.5 × 2 = 167 ...(ii)
⇒ B = 167 - X ...(iii)
A + X = 89 × 2 = 178 ...(iv)
⇒ A = 178 - X ...(v)
Substitute (iii) and (v) in (i) and solve for <em>X</em> as follows:
A + X + B = 261
178 - X + X + 167 - X = 261
345 - X = 261
X = 84
Substitute the value of <em>X</em> in (iii) and solve for B as follows:
B = 167 - X
= 167 - 84
= 83
Substitute the value of <em>X</em> in (v) and solve for A as follows:
A = 178 - X
= 178 - 84
= 94
Thus, the highest score is 94.
