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olga55 [171]
3 years ago
15

Use counting arguments from the preceding chapter. My couch potato friend enjoys sitting in front of the TV and grabbing handful

s of 5 chocolates at random from his snack jar. Unbeknownst to him, I have replaced one of the 20 chocolates in his jar with a cashew. (He hates cashews with a passion.) How many possible outcomes are there the first time he grabs 5 chocolates?
Mathematics
1 answer:
den301095 [7]3 years ago
7 0

Answer:

The total possible outcomes are 15,504.

Step-by-step explanation:

Consider the provided information.

My couch potato friend enjoys sitting in front of the TV and grabbing handfuls of 5 chocolates at random from his snack jar.

The jar has 20 items and we need to find the possible outcomes are there the first time he grabs 5 chocolates.

Here the sample space S is the set of 5 chocolates.

n(S)=C(20,5)

Therefore,

C(20,5)=\frac{20!}{5!(20-5)!}

C(20,5)=\frac{20!}{5!15!}

C(20,5)=15504

Hence, the total possible outcomes are 15,504.

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Double the sum of a number and three is the same as the number subtracted by nine
OleMash [197]

Answer:

2(n+3) = n-9

Step-by-step explanation:

2(n+3) = n-9

Step 1: Multiply (n+3) by two; 2n + 6

Step 2: Subtract n on both sides; n+6= -9

Step 3: Subtract 6 on both sides; n= -9 - 6

Step 4: Add -9 and -6; -15

Solution: n= -15

4 0
3 years ago
Eli bought a jacket that was on sale at 40 percent off. The original price of the jacket was $60.00. How much did Eli pay?
Elis [28]

Answer:

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Step-by-step explanation:

40% of 60 is 24. Subtract from the origanl amount, you get the price after sale, $36.00. Hope this helps :)

7 0
3 years ago
Find the slope of the line through each pair of points (20,-16),(19-16)
ale4655 [162]

Answer:

Undefined slope.

Step-by-step explanation:

The formula should be y2 - y1 over x2 - x1

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So ( -16 - ( -16 ) ) over ( 19 - 20 )

0 over -1

The slope is 0. Undefined.

3 0
3 years ago
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Step-by-step explanation:

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3 years ago
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A polynomial equation with rational coefficients has the roots 7 + *sqrt* 3 , 2 - *sqrt* 6. Find two additional roots.
Ganezh [65]

Answer:

option: A

Step-by-step explanation:

" if for a polynomial with rational coefficients has irrational roots then these irrational roots will always appear in pair " .

we are given that 7+\sqrt{3} and 2-\sqrt{6} are two roots of a polynomial equation with rational coefficients, then it's complex conjugate is also a root of this polynomial equation i.e. ' 7-\sqrt{3} ' and '  2+\sqrt{6} ' are also roots of this polynomial equation.

Hence, option A is correct.


5 0
3 years ago
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