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4 years ago

Write a recursive formula for the arithmetic sequence below. What is the value of the 8th term?

Mathematics

2 answers:

Rufina [12.5K]4 years ago

7 0

Answer:

Value of the 8th term = 29

Step-by-step explanation:

We have to write a recursive formula for the arithmetic sequence given as 1, 5, 9, 13......

For an arithmetic sequence recursive formula is

$T_{n}=1+(n-1)4$

= 1 + 4n - 4

$T_{n}=4n-3$

Now 8th term will be $T_{8}$ = ( 4 × 8 - 3 )

= 32 - 3

= 29

Value of the 8th term = 29

Bumek [7]4 years ago

4 0

To find the answer,

Multiply the term with 4 then subtract with 3

Lets take the term as 'n'

Formula = 4n-3

Value of 8th term = (4*8)-3
= 32-3
= 29

The value of 8th term is 29

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About 0.72

Step-by-step explanation:

Given the data:

With device : 22.6, 23.4, 28.4, 29, 29.3, 20.0

Without device :26.9, 24.4, 20.8, 20.8, 20.2, 26.0, 28.1, 25.6

Using calculator:

With device data:

Sample size (n1) = 6

Degree of freedom (df1) = 6 - 1 = 5

Mean(m1) = 25.45

Variance (s²1) = 15.631

Without device data:

Sample size (n2) = 8

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Mean (m2) = 24.1

Variance (s²2) = 9.54

s²t = ((df1/(df1 + df2)) * s²1) + ((df2/(df1 + df2)) * s²2)

s²t = ((5/(5+7)*15.63) + ((7/(5+7))*9.54)

= ((5/12) * 15.63) + ((7/12) * 9.54) = 12.0775

s²m1 = s²t/n1 = 12.0775/6 = 2.0123

s²m2 = s²t/n2 = 12.0775/8 = 1.511

T - statistic :

Tstat = (m1 - m2)/√(s²m1 + s²m2)

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2 years ago

Solve the system by substitution. y=4x-9 y=x-3

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2 years ago

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The composite figures below are made of right prisms.

Mkey [24]

Answer:

Figure 1's surface area: 550 $feet^2$

Figure 2's surface area: 530 $feet^2$

Figure 3's surface area: 790 $feet^2$

So, the order of the figures' surface areas is: Figure 2 < Figure 1 < Figure 3.

Step-by-step explanation:

Bearing in mind that the surface area of a 3D object is the total area of its surface (that is the sum of the areas of its faces), we can count the number of distinct shapes in each figure, calculate their areas and add them up. Be careful not to add the faces that are "inside".

Figure 1

Its surface area consists of 13 squares of 5x5 $feet^2$ and 3 rectangles of 15x5 $feet^2$ . So, its surface area is (13x25 + 3x75) $feet^2 = 550feet^2$

Figure 2

Its surface area consists of 6 squares of 5x5 $feet^2$ , 3 rectangles of 17x5 $feet^2$ , 1 rectangle of 13x5 $feet^2$ and 2 triangles of base 12 feet and height 5 feet. So, its surface area is (17x5x3+6x5x5+13x5+12x5x2:2) $feet^2 = 530feet^2$

Figure 3

Its surface area consists of 2 rectangles of 12.5x5 $feet^2$ , 1 rectangle of 11x5 $feet^2$ , 2 triangles of base 12 feet and height 5 feet, 1 rectangle of 11x13 $feet^2$ , 2 rectangles of 12.5x11 $feet^2$ and 1 rectangle of 12x11 $feet^2$ .

So, its surface area is (2x12.5x5+11x5+2x12x5:2+11x13+2x12.5x11+12x11) $feet^2 = 790feet^2$

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3 years ago

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