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kari74 [83]
3 years ago
7

Given: g(x) = 3x² + 2 and h(x) = 2x + 2 Find: g(h(x))

Mathematics
1 answer:
kompoz [17]3 years ago
7 0

Step-by-step explanation:

g(x) = 3x² + 2

h(x) = 2x + 2

g(h(x)) = g([2x + 2]) = 3[2x+2]² + 2

= 3[4x² + 8x + 4] + 2

= 12x² + 24x + 12 + 2

= 12x²+ 24x + 14

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How can you determine if a number is a rational number
Murljashka [212]
Rational numbers can be written as a fraction
7 0
3 years ago
What is the x value 5x+8-3x=-10
otez555 [7]
5x + 8 - 3x = 10
First you can combine the like terms.
5x - 3x + 8 = 10
2x + 8 = 10
     - 8     - 8
2x = 2
\frac{2x}{2} =  \frac{2}{2}
x=1
3 0
3 years ago
Read 2 more answers
I need help with these two questions please!!!please HeLp mE
Hatshy [7]

Answer:

5, 2, 1, 2, 3

Step-by-step explanation:

5 0
3 years ago
HELP ASAP<br><br> Write the equation of the line passing through the points (-5,8) and (-8,5).
ycow [4]

Answer:

y=-5/8x+0

Step-by-step explanation:

8 0
3 years ago
If possible help me in this. I need to find the two odd numbers...​
Lelechka [254]

Part (a)

Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer

For example, if x = 7, then x+2 = 9 is right after.

<h3>Answer:  x+2</h3>

========================================================

Part (b)

The consecutive odd integers we're dealing with are x and x+2.

Their squares are x^2 and (x+2)^2, and these squares add to 394.

<h3>Answer: x^2 + (x+2)^2 = 394</h3>

========================================================

Part (c)

We'll solve the equation we just set up.

x^2 + (x+2)^2 = 394

x^2 + x^2 + 4x + 4 = 394

2x^2+4x+4-394 = 0

2x^2+4x-390 = 0

2(x^2 + 2x - 195) = 0

x^2 + 2x - 195 = 0

You could factor this, but the quadratic formula avoids trial and error.

Use a = 1, b = 2, c = -195 in the quadratic formula.

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\

If x = 13, then x+2 = 13+2 = 15

Then note how x^2 + (x+2)^2 = 13^2 + 15^2 = 169 + 225 = 394

Or we could have x = -15 which leads to x+2 = -15+2 = -13

So, x^2 + (x+2)^2 = (-15)^2 + (-13)^2 = 225 + 169 = 394

We get the same thing either way.

<h3>Answer: Either 13, 15  or  -15, -13</h3>
4 0
3 years ago
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