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Sidana [21]
3 years ago
14

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics
1 answer:
Yakvenalex [24]3 years ago
8 0

Answer: (C) even

<u>Step-by-step explanation:</u>

A function is even when f(x) = f(-x)

A function is odd when f(-x) = -f(x)


f(x) = -2x⁴ + 3x²

f(-x) = -2(-x)⁴ + 3(-x)²

      = -2x⁴ + 3x²

f(x) = f(-x) so the function is even


-f(x) = -(-2x⁴ + 3x²)

       = 2x⁴ - 3x²

f(-x) ≠ -f(x) so the function is not odd.

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Rationalise the denominator
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Answer:

sqrt(3) /3

Step-by-step explanation:

1 / sqrt(3)

Multiply the top and bottom by sqrt(3)

1/ sqrt(3) * sqrt(3)/ sqrt(3)

sqrt(3) /  sqrt(3)*sqrt(3)

sqrt(3) /3

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3 years ago
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8 0
3 years ago
Which of the following equations matches the function shown above?
yanalaym [24]

Answer:

C=y=sin1/2x

Step-by-step explanation:

As given in the graph:

Amplitude= 1

period=2π

Finding function of sin that have period of 4π and amplitude 1

A: y=1/2sinx

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1/2

b=1

c=0

d=0

Amplitude=|a|

                =1/2

Period= 2π/b

         =2π

B: y=sin2x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=2

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/2

         =π

C: y=sin1/2x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=1/2

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/1/2

         =4π

D: y=sin1/4x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=1/4

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/1/4

         =8π

Hence only c: y=sin1/2x has period of 2π and amplitude 1

5 0
3 years ago
Whats 12y=9x-30 in standard form
nadya68 [22]
Standard form : Ax + By = C

12y = 9x - 30
-9x + 12y = -30 ....some teachers accept this, with A being negative
but if not, then it is this :
9x - 12y = 30
7 0
3 years ago
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