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3 years ago

7

Has one endpoint and it continues in the other direction

2 answers:

Salsk061 [2.6K]3 years ago

5 0

Answer is a ray. I hope this helped, good luck :)

neonofarm [45]3 years ago

3 0

Ray is the answer,hope this helps

You might be interested in

Solve: -3 |x-3| = -6 <br>how do i solve absoulute value ?

Marizza181 [45]

Answer:

x=5,1

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

3 0

3 years ago

Let c be a positive number. A differential equation of the form dy/dt=ky^1+c where k is a positive constant, is called a doomsda

stich3 [128]

Answer:

The doomsday is 146 days

<em></em>

Step-by-step explanation:

Given

$\frac{dy}{dt} = ky^{1 +c}$

First, we calculate the solution that satisfies the initial solution

Multiply both sides by

$\frac{dt}{y^{1+c}}$

$\frac{dt}{y^{1+c}} * \frac{dy}{dt} = ky^{1 +c} * \frac{dt}{y^{1+c}}$

$\frac{dy}{y^{1+c}} = k\ dt$

Take integral of both sides

$\int \frac{dy}{y^{1+c}} = \int k\ dt$

$\int y^{-1-c}\ dy = \int k\ dt$

$\int y^{-1-c}\ dy = k\int\ dt$

Integrate

$\frac{y^{-1-c+1}}{-1-c+1} = kt+C$

$-\frac{y^{-c}}{c} = kt+C$

To find c; let t= 0

$-\frac{y_0^{-c}}{c} = k*0+C$

$-\frac{y_0^{-c}}{c} = C$

$C =-\frac{y_0^{-c}}{c}$

Substitute $C =-\frac{y_0^{-c}}{c}$ in $-\frac{y^{-c}}{c} = kt+C$

$-\frac{y^{-c}}{c} = kt-\frac{y_0^{-c}}{c}$

Multiply through by -c

$y^{-c} = -ckt+y_0^{-c}$

Take exponents of $-c^{-1$

$y^{-c*-c^{-1}} = [-ckt+y_0^{-c}]^{-c^{-1}$

$y = [-ckt+y_0^{-c}]^{-c^{-1}$

$y = [-ckt+y_0^{-c}]^{-\frac{1}{c}}$

i.e.

$y(t) = [-ckt+y_0^{-c}]^{-\frac{1}{c}}$

Next:

$t= 3$ i.e. 3 months

$y_0 = 2$ --- initial number of breeds

So, we have:

$y(3) = [-ck * 3+2^{-c}]^{-\frac{1}{c}}$

-----------------------------------------------------------------------------

We have the growth term to be: $ky^{1.01}$

This implies that:

$ky^{1.01} = ky^{1+c}$

By comparison:

$1.01 = 1 + c$

$c = 1.01 - 1 = 0.01$

$y(3) = 16$ --- 16 rabbits after 3 months:

-----------------------------------------------------------------------------

$y(3) = [-ck * 3+2^{-c}]^{-\frac{1}{c}}$

$16 = [-0.01 * 3 * k + 2^{-0.01}]^{\frac{-1}{0.01}}$

$16 = [-0.03 * k + 2^{-0.01}]^{-100}$

$16 = [-0.03 k + 0.9931]^{-100}$

Take -1/100th root of both sides

$16^{-1/100} = -0.03k + 0.9931$

$0.9727 = -0.03k + 0.9931$

$0.03k= - 0.9727 + 0.9931$

$0.03k= 0.0204$

$k= \frac{0.0204}{0.03}$

$k= 0.68$

Recall that:

$-\frac{y^{-c}}{c} = kt+C$

This implies that:

$\frac{y_0^{-c}}{c} = kT$

Make T the subject

$T = \frac{y_0^{-c}}{kc}$

Substitute: $k= 0.68$ , $c = 0.01$ and $y_0 = 2$

$T = \frac{2^{-0.01}}{0.68 * 0.01}$

$T = \frac{2^{-0.01}}{0.0068}$

$T = \frac{0.9931}{0.0068}$

$T = 146.04$

<em>The doomsday is 146 days</em>

4 0

3 years ago

Which benefits do employers commonly offer to full-time employees?

Ilya [14]

Health insurance atleast that’s what I think

4 0

4 years ago

Read 2 more answers

Compute the probability that a hand of 13 cards contains all 4 of at least 1 of the 13 denominations.answer: 0.0343

gogolik [260]

The probability of a hand of 13 cards contains all 4 of one of the denominations, say Aces, is given by:
$\frac{4C4\times48C9}{52C13}=0.00264106$
The same probability applies to getting all 4 of each of the other denominations.
Therefore the required probability is:
$0.00264106\times13=0.0343$
The answer is 0.0343.

5 0

3 years ago

A plain pizza cost $8.35. Additional toppings cost $0.95 each. Which equation can be used to represent the cost of a pizza, y, w

Yakvenalex [24]

Answer: y=0.95x+8.35

Step-by-step explanation: Hi there.

We can use the equation y=mx+b, where

y=the result (in this case the cost of the pizza)

m=the slope (how much each topping costs)

x=input value (how many kinds of toppings the pizza has)

b=initial value (how much the plain pizza costs)

The toppings cost $0.95, and the value of the plain pizza is $8.35

So the equation is: y=0.95x+8.35.

Have a nice day! :)

7 0

3 years ago