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Nutka1998 [239]
3 years ago
8

On a summer day, you take a road trip through Death Valley, California, in an antique car. You start out at a temperature of 21°

C, but the temperature in Death Valley will reach a peak of 51°C. The tires on your car hold 15.6 L of nitrogen gas at a starting pressure of 249 kPa. The tires will burst when the internal pressure (Pb) reaches 269 kPa. Answer the following questions and show your work.
How many moles of nitrogen gas are in each tire?
• What will the tire pressure be at peak temperature in Death Valley?
• Will the tires burst in Death Valley? Explain.
• If you must let nitrogen gas out of the tire before you go, to what pressure must you reduce the tires before you start your trip? (Assume no significant change in tire volume.)
Chemistry
1 answer:
MrRissso [65]3 years ago
4 0
<span>There is only one formula to use and we should assume ideal gas. This equation is: PV=nRT. For the following questions manipulate this equation to get the answer.
 1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol
 2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa
 3. Since the answer in #2 is more than 269 kPa, then the tires will likely burst. 4. Reduce pressure way below the limit 269 kPa.</span>
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3 years ago
4. Explain why 50 g of liquid water at 0°C heats-up more quickly than 50 g of an ice water mixture at 0°C under the same conditi
Minchanka [31]
4) the ice has to be heated up to above 0c first, as it is continuing to cool the water back toward 0c
5) 0.0338 kcal
(33.8/1000)
6) 1.2506 kcal
((33.8*37.0)/1000)
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4 years ago
What passes through the Haversian canal
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4 0
3 years ago
How many atoms of fluorine are in 5.6×1022 molecules of MgF2?
VashaNatasha [74]

Answer:You can set up stoichiemetry using the following equation:

(15.6 g MgF2) x (38g F / 62g MgF2) x (6.022x10^23 / 19gF)

= 3.03 x 10^23 molecules of F

or 1.52 x 10^23 molecules of F2

The number of molecules of magnesium fluoride in 15.6 g of MgF2 has to be found.

The molecular mass of MgF2 is 62.3018. 15.6 g of MgF2 is equivalent to 15.6/62.3018 mole of MgF2.

One mole of a gas has 6.02214179*10^23 particles.

15.6/62.3018 mole of MgF2 has (15.6/62.3018)*6.02214179*10^23 molecules of the compound.

(15.6/62.3018)*6.02214179*10^23

=> 1.5079*20^23

If this is rounded to one decimal figure the result is 1.51*10^23.

The number of molecules of MgF2 in 15.6 g of the gas is 1.51*10^23.

3 0
3 years ago
4.45 kcal of heat was added to increase the temperature of a sample of water from 23.0 °C to 57.8 °C. Calculate
Alona [7]

Answer:

m = 4450 g

Explanation:

Given data:

Amount of heat added = 4.45 Kcal ( 4.45 kcal ×1000 cal/ 1kcal = 4450 cal)

Initial temperature = 23.0°C

Final temperature = 57.8°C

Specific heat capacity of water = 1 cal/g.°C

Mass of water in gram = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 57.8°C - 23.0°C

ΔT = 34.8°C

4450 cal = m × 1 cal/g.°C × 34.8°C

m = 4450 cal / 1 cal/g

m = 4450 g

4 0
3 years ago
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