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3 years ago

Given 65 g of C3 H8 and 65 g of O2, what is the theoretical yield of CO2 in grams

Chemistry

1 answer:

Helga [31]3 years ago

7 0

Answer:

Yeild of CO2 is approximately 54g

Explanation:

Using reaction stoichiomety and coeeficients, and knowing O2 is limiting reactant, 54 g of CO2 is produced.

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John rode 3150 m at an average speed of 350 m/min.If he had ridden at average of 375 m/min instead. How much sooner would it hav

Svet_ta [14]

Explanation:

Given that:

Distance traveled = 3150m

Average speed = 350m/min

Suggested speed = 375m/min

Unknown:

Time = ?

Solution:

Speed is the rate of change of distance with time.

it is mathematically expressed as;

speed = $\frac{distance }{time}$

Initial time using speed 350m/min can be calculated by making time the subject of the formula;

time taken = $\frac{distance }{speed}$

time taken at speed of speed of 350m/min = $\frac{3150}{350}$ = 9min

to seconds = 9 x 60 = 540 seconds

time taken at speed of 375m/min = $\frac{3150}{375}$ = 8.4min

to seconds = 8.4 x 60 = 504 seconds.

It could have taken 504 seconds sooner saving 36 seconds.

learn more:

Speed brainly.com/question/10177389

#learnwithBrainly

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3 years ago

Particles in a liquid move around just as freely as particles in a solid.

andre [41]

It is false :D I am 95% sure

5 0

2 years ago

Read 2 more answers

Glycerol (molar mass 92.09 g/mol) has been suggested for use as an alternative fuel. The enthalpy of combustion, Δ

victus00 [196]

The mass of glycerol to that would need to be combusted to heat 500.0g of water from 20.0°C to 100.0°C is; 9.32 grams.

We must establish the fact that energy is neither created nor destroyed.

Therefore, the amount of heat absorbed by water is equal to the amount of heat released by the combustion of glycerol.

Total heat absorbed by water, H(water) is;

Q(water) = m C (T2 - T1)

Q(water) = 500 × 4.184 × (100-20)

Q(water) = 167.36 kJ

Consequently, the quantity of heat evolved by the combustion of glycerol is;

Q(glycerol) = 167,360 J = n × ΔH°comb

where, n = no. of moles of glycerol.

167.36 kJ= n × 1654 kJ/mole

n = 167.36/1654

n = 0.1012 moles of glycerol.

Therefore, mass of glycerol combusted, m is;

m = n × Molar mass

m = 0.1012 × 92.09

m = 9.32 g.

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2 years ago

How many grams are in 1 mole of Ar?

Ilia_Sergeevich [38]

Answer: 39.948 grams

Explanation:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Ar, or 39.948 grams

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3 years ago

_H2 SiCl2 + _H2O −−→ _H8 Si4O4 + _HCl

Serjik [45]

Answer:

Explanation:

pls mark brainliest right

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2 years ago