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nikitadnepr [17]
4 years ago
6

-5(-× -6) =31 Solve the equation

Mathematics
1 answer:
faust18 [17]4 years ago
6 0

Answer: I believe the answer to this question is: X= 1/5.

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What the function?<br> y = 2.5x + 8
garik1379 [7]

Answer:

Step-by-step explanation:

This is a linear function with y-intercept (0, 8) and slope 2.5.

6 0
3 years ago
8. Which of the following correctly multiplies f(x) x g(x) if f(x) = 3x-1 and g(x) = 2x + 1?
raketka [301]

Answer:

C) f(x) x g(x) = 6x2 + x-1

Step-by-step explanation:

Multiplication of functions:

Two multiply two polynomial functions, we apply the distributive property(multiply each two terms and add).

In this question, we have that:

f(x) = 3x - 1, g(x) = 2x + 1

The multiplication is:

f(x) \times g(x) = (3x - 1)(2x+1) = 3x*2x + 3x*1 -1*2x -1*1 = 6x^2 + 3x - 2x - 1 = 6x^2 + x - 1

The correct answer is given by option C.

4 0
3 years ago
URGENT<br><br> question is in the photo :)
fredd [130]

1. b¹²

2. 2x⁴

3. 3x³

4. 6x¹¹

5. 10x⁹

6 0
3 years ago
(11x + 2y) - (5x – y)
omeli [17]

Answer:

the answer is 6x+3y

Step-by-step explanation:

\mathrm{Remove\:parentheses}:\\=11x+2y-\left(5x-y\right)\\\\-(5x-y): -5x+y\\=11x+2y-5x+y\\Simplify:\\11x+2y-5x+y: 6x+3y\\\\=6x+3y

hope this helps :)

Try using Symbolab, I use it all the time it gives the correct answer and it gives good explanations.

5 0
3 years ago
How do you cross multiply
Dennis_Churaev [7]
I'll add a picture so it can make more sense to you. :)

We'll use the picture below as an example okay? :)
What you want to do is m<span>ultiply the numerator (top number) of the left-hand fraction by the denominator (bottom number) of the right-hand fraction. Then multiply the numerator (top number) of the right-hand fraction by the denominator (bottom number) of the left-hand fraction. Next step is to set the two products equal to each other. Then s<span>olve for the variable. If you look at the picture while reading the steps, then I think it'll make more sense.
I really hope this helps :)</span></span>

4 0
4 years ago
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