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Igoryamba
3 years ago
7

When sam goes to a restaurant, he always tips the server $2 plus 10% of the cost of the meal. if sam’s distribution of meal cost

s has a mean of $9 and a standard deviation of $3, what are the mean and standard deviation of the distribution of his tips?
Business
1 answer:
o-na [289]3 years ago
5 0
Given that S<span>am's distribution of meal costs has a mean of $9 and a standard deviation of $3, this means that the range of Sam's meal cost that are within one standard deviation is given by ($9 - 3, $9 + 3) = ($6, $12).

Given that Sam </span><span>always tips the server $2 plus 10% of the cost of the meal, this means that when the cost of the meal is $9, Sam tips $2 + (0.1 x 9) = $2 + $0.9 = $2.90

Therefore, the mean of the distribution of Sam's tips is $2.90

Similarly, the </span><span>range of Sam's tips that are within one standard deviation is given by ($2 + 0.1(6), $2 + 0.1(12)) = ($2 + 0.6, $2 + 1.2) = ($2.6, 3.2) = ($2.9 - $0.3, $2.9 + $0.3)

Therefore, </span><span>the standard deviation of the distribution of Sam's tips is $0.3</span>
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Answer:

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Explanation:

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Deprecation base=Acquisition Cost-Salvage Value

Acquisition Cost:

It is the cost which involves the buying of asset and making the asset to work. In our case:

Acquisition Cost=Cost of machine+Tax+Fees+Shipping charges+Paid to contractor to build and wire a platform for the machine

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Deprecation base=Acquisition Cost-Salvage Value

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Deprecation base=$26,300

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