Answer:
Length:8 m
Width:3 m
Step-by-step explanation:
<u><em>The complete question is</em></u>
If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.
step 1
<em>Perimeter of rectangle</em>
we know that
The perimeter of rectangle is equal to

we have

so

Simplify
-----> equation A
step 2
Perimeter of triangle
The perimeter of triangle is equal to


so

Multiply by 2 both sides

----> equation B
Solve the system of equations by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point (8,3)
see the attached figure
therefore
The dimensions of the rectangle are
Length:8 m
Width:3 m
Answer:
Approximately $594.38
Step-by-step explanation:
Use the formula: y = a(1 + r)^t
a is the initial amount
r is the percent of interest in decimal form
t is the time in years
y is the money after t years
Substitute the values given in the problem into the equation:
400(1+0.02)^20
Use a calculator or solve manually
Around 594.38
Answer:
Length: 3w-4
Step-by-step explanation:
Length: 3w-4
Width: W
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You said 2x - 9 < 7
Add 9 to each side: 2x < 16
Divide each side by 2 : x < 8 .